Advertisements
Advertisements
प्रश्न
If a2 + b2 + c2 = 250 and ab + bc + ca = 3, find a + b + c.
Advertisements
उत्तर
Recall the formula
`(a+b+c)^2 = a^2 +b^2 +c^2 + 2(ab + bc + ca)`
Given that
`a^2 + b^2 + c^2 = 250 , ab + bc + ca = 3 `
Then we have
`(a+b+c)^2 = a^2 + b^2 + c^2 + 2 (ab + bc+ca)`
`(a+b+c)^2 = 250 + 2.(3)`
`(a+b+c)^2 = 256`
`(a+b+c) =± 16`
APPEARS IN
संबंधित प्रश्न
`(x/2 + y + z/3)^3 + (x/2 + (2y)/3 + z)^3 + (-(5x)/6 - y/3 - (4z)/3)^3`
If a + b + c = 0, then write the value of a3 + b3 + c3.
Multiply: (2x + 3y)(2x - 3y)
Divide: 6x2 + 5x - 6 by 2x + 3
Divide: 15x2 + 31xy + 14y2 by 5x + 7y
Divide: 6x3 + 5x2 − 21x + 10 by 3x − 2
Divide: 5x2 - 3x by x
The simplest form of 5 ÷ `(3/2) - 1/3` is ______.
A taxi service charges ₹ 8 per km and levies a fixed charge of ₹ 50. Write an algebraic expression for the above situation, if the taxi is hired for x km.
Which of the following is an example of a monomial?
