Advertisements
Advertisements
प्रश्न
If a2 + b2 + c2 = 250 and ab + bc + ca = 3, find a + b + c.
Advertisements
उत्तर
Recall the formula
`(a+b+c)^2 = a^2 +b^2 +c^2 + 2(ab + bc + ca)`
Given that
`a^2 + b^2 + c^2 = 250 , ab + bc + ca = 3 `
Then we have
`(a+b+c)^2 = a^2 + b^2 + c^2 + 2 (ab + bc+ca)`
`(a+b+c)^2 = 250 + 2.(3)`
`(a+b+c)^2 = 256`
`(a+b+c) =± 16`
APPEARS IN
संबंधित प्रश्न
Factorize x2 - y2 - 4xz + 4z2
Factorize `x^2 + 6sqrt2x + 10`
Factorize `x^2 + 2sqrt3x - 24`
Factorize 64a3 +125b3 + 240a2b + 300ab2
8x3 + 27y3 - 216z3 + 108xyz
If \[x^2 + \frac{1}{x^2} = 18,\] find the values of \[x + \frac{1}{x} \text { and } x - \frac{1}{x} .\]
Evaluate: (3c - 5d)(4c - 6d)
Divide: 4a2 + 4a + 1 by 2a + 1
Divide: 3y3 - 9ay2 - 6ab2y by -3y
Shiv works in a mall and gets paid ₹ 50 per hour. Last week he worked for 7 hours and this week he will work for x hours. Write an algebraic expression for the money paid to him for both the weeks.
