Advertisements
Advertisements
प्रश्न
The area of a rectangle is 6x2 – 4xy – 10y2 square unit and its length is 2x + 2y unit. Find its breadth.
Advertisements
उत्तर
Area of a rectangle
= 6x2 - 4xy - 10y2 sq.units
Length = 2x + 2y units
∴ Breadth = `"Area"/"Length"`
`= ("6x"^2 - 4"xy" - 10"y"^2)/"2x + 2y"`
3x - 5y
`"2x" + "2y")overline(6"x"^2 - 4"xy" - 10"y"^2)(`
6x2 + 6xy
- -
- 10xy - 10y2
- 10xy - 10y2
+ +
xxxx
= 3x - 5y units
Hence breadthy = 3x - 5y units
APPEARS IN
संबंधित प्रश्न
Factorize : x2 + y - xy - x
Factorize `2x^2 + 3sqrt5x + 5`
Factorize the following expressions
64a3 – b3
Factorize the following expressions:
x3 + 6x2 +12x +16
The factors of 8a3 + b3 − 6ab + 1 are
Divide: 4x3 - 2x2 by - x
Divide: 9x2 - 24xy + 16y2 by 3x- 4y
Express the following as an algebraic expression:
The product of x and y divided by m.
Solve the following equation.
4(x + 12) = 8
Give an algebraic equation for the following statement:
“The difference between the area and perimeter of a rectangle is 20”.
