Advertisements
Advertisements
प्रश्न
The area of a rectangle is 6x2 – 4xy – 10y2 square unit and its length is 2x + 2y unit. Find its breadth.
Advertisements
उत्तर
Area of a rectangle
= 6x2 - 4xy - 10y2 sq.units
Length = 2x + 2y units
∴ Breadth = `"Area"/"Length"`
`= ("6x"^2 - 4"xy" - 10"y"^2)/"2x + 2y"`
3x - 5y
`"2x" + "2y")overline(6"x"^2 - 4"xy" - 10"y"^2)(`
6x2 + 6xy
- -
- 10xy - 10y2
- 10xy - 10y2
+ +
xxxx
= 3x - 5y units
Hence breadthy = 3x - 5y units
APPEARS IN
संबंधित प्रश्न
Factorize `6ab - b^2 + 12ac - 2bc`
If x − y = 7 and xy = 9, find the value of x2 + y2
Find the value of the following expression: 64x2 + 81y2 + 144xy, when x = 11 and \[y = \frac{4}{3}\]
Find the value of the following expression: 81x2 + 16y2 − 72xy, when \[x = \frac{2}{3}\] and \[y = \frac{3}{4}\]
Write the number of the term of the following polynomial.
ax – by + y x z
Write the number of the term of the following polynomial.
23 + a x b ÷ 2
Divide: m2 − 2mn + n2 by m − n
Divide: x2 + 4xy + 4y2 by x + 2y
The value of 7a – 4b when a = 3, b = 2 is
Will the value of 11x for x = –5 be greater than 11 or less than 11? Explain.
