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प्रश्न
Factorize `6ab - b^2 + 12ac - 2bc`
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उत्तर
Taking common b in (6ab - b2 )and 2c in (12ac - 2bc)
= b (6a - b) + 2c (6a - b)
Taking (6a - b) common in both terms
= (6a - b)(b + 2c)
∴ 6ab - b2 +12ac - 2bc = (6a - b)(b + 2c)
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