Advertisements
Advertisements
प्रश्न
Factorize `6ab - b^2 + 12ac - 2bc`
Advertisements
उत्तर
Taking common b in (6ab - b2 )and 2c in (12ac - 2bc)
= b (6a - b) + 2c (6a - b)
Taking (6a - b) common in both terms
= (6a - b)(b + 2c)
∴ 6ab - b2 +12ac - 2bc = (6a - b)(b + 2c)
APPEARS IN
संबंधित प्रश्न
What are the possible expressions for the dimensions of the cuboid whose volume is 3x2 - 12x.
Factorize the following expressions
1- 27a3
Factorize the following expressions:
( x + 2)3 + ( x - 2)3
`1/27 x^3 - y^3 + 125z^3 + 5xyz`
(a – 3b)3 + (3b – c)3 + (c – a)3
Divide: 25x2y by - 5y2
Write the coefficient of x2 and x in the following polynomials
`4 + 2/5x^2 - 3x`
If x = 2 and y = 3, then find the value of the following expressions
x + y
Number of terms in the expression a2 + bc × d is ______.
Express the following properties with variables x, y and z.
Associative property of addition
