Advertisements
Advertisements
प्रश्न
Factorize `6ab - b^2 + 12ac - 2bc`
Advertisements
उत्तर
Taking common b in (6ab - b2 )and 2c in (12ac - 2bc)
= b (6a - b) + 2c (6a - b)
Taking (6a - b) common in both terms
= (6a - b)(b + 2c)
∴ 6ab - b2 +12ac - 2bc = (6a - b)(b + 2c)
APPEARS IN
संबंधित प्रश्न
Factorize the following expressions
8x3 y3 + 27a3
Factorize 8a3 + 27b3 + 36a2b + 54ab2
Separate monomials, binomials, trinomials and polynomials from the following algebraic expressions :
8 − 3x, xy2, 3y2 − 5y + 8, 9x − 3x2 + 15x3 − 7,
3x × 5y, 3x ÷ 5y, 2y ÷ 7 + 3x − 7 and 4 − ax2 + bx + y
Multiply: (-2x + 3y)(2x - 3y)
Divide: 2a2 - 11a + 12 by a - 4
Write the coefficient of x2 and x in the following polynomials
`sqrt(3)x^2 + sqrt(2)x + 0.5`
Write the variables, constant and terms of the following expression
18 + x – y
The value of 3x2 – 5x + 3 when x = 1 is ______.
Shashi used addition to solve a word problem about the weekly cost of commuting by toll tax for ₹ 15 each day. Ravi solved the same problem by multiplying. They both got the correct answer. How is this possible?
Which of the following is an example of a monomial?
