Advertisements
Advertisements
प्रश्न
Multiply: x2 + 4y2 + 2xy − 3x + 6y + 9 by x − 2y + 3
Advertisements
उत्तर
The given expression is
`x^2 +4y^2 +2xy -3x +6y+9`
We have to multiply the above expression by (x - 2y +3).
The required product is
`(x-2y+3)(x^2 +4y^2 +2xy - 3x +6y +9)`
` = {x+(-2y)+3}{(x)^2 + (-2y)^2 +(3)^2 -x.(-2y) -(-2y).(3) - (3).x}`
Recall the formula
`a^3+b^3 +c^3-3abc = (a+b+c)(a^2 +b^2 +c^2 - ab - bc-ca)`
Using the above formula, we have
` = x^3 +(-2y)^3 + (3)^3 - 3.x.(-2y).(3)`
` = x^3 -8y^3 +27 +18xy`
APPEARS IN
संबंधित प्रश्न
Factorize x4 + x2 y2 + y4
Factorize `5sqrt5x^2 + 20x + 3sqrt5`
Factorize the following expressions:
( x + 2)3 + ( x - 2)3
Factorize the following expressions:
a12 + b12
Factorize 8x3 + 27 y3 + 36x2 y + 54xy2
Factorize x3 -12x ( x - 4) - 64
The factors of x3 − 1 + y3 + 3xy are
The value of 7a – 4b when a = 3, b = 2 is
Shiv works in a mall and gets paid ₹ 50 per hour. Last week he worked for 7 hours and this week he will work for x hours. Write an algebraic expression for the money paid to him for both the weeks.
How many terms does a trinomial contain?
