Advertisements
Advertisements
प्रश्न
Factorize a3 – 3a2b + 3ab2 – b3 + 8
Advertisements
उत्तर
a3 - 3a2b + 3ab2 - b3 + 8
= (a - b)3 + 8 [∵ a3 - b3 - 3a2b + 3ab2 = (a - b)3
= (a - b)3 + 23
= (a - b + 2)((a - b)2 - (a - b)2 + 22 ) [∵ a3 + b3 = (a + b)(a2 - ab + b2)]
= (a - b + 2)(a2 + b2 - 2ab - 2(a - b) + 4)
= (a - b + 2)(a2 + b2 - 2ab - 2a + 2b + 4)
∴ a3 - 3a2b + 3ab2 - b3 + 8 = (a - b + 2)(a2 + b2 - 2ab - 2a + 2b + 4)
APPEARS IN
संबंधित प्रश्न
Factorize x2 - y2 - 4xz + 4z2
Factorize `x^2 + 6sqrt2x + 10`
Factorize `9(2a - b)^2 - 4(2a - b) - 13`
Factorize the following expressions:
x3 + 6x2 +12x +16
Find the value of the following expression: 16x2 + 24x + 9, when \[x = \frac{7}{4}\]
The factors of x4 + x2 + 25 are
Divide: 8x + 24 by 4
Divide: 6x2 - xy - 35y2 by 2x - 5y
Express the following as an algebraic expression:
The product of 12, x, y and z minus the product of 5, m and n.
If x = 2 and y = 3, then find the value of the following expressions
2x – 3y
