Advertisements
Advertisements
प्रश्न
Factorize `9(2a - b)^2 - 4(2a - b) - 13`
Advertisements
उत्तर
Let 2a - b = x
= 9x2 - 4x -13
Splitting the middle term,
= 9x2 -13x + 9x -13
= x (9x -13) +1(9x -13)
= (9x -13)( x +1)
Substituting x = 2a - b
= [9 (2a - b) -13] (2a - b +1)
= (18a - 9b -13)(2a - b +1)
∴ 9(2a - b)2 - 4(2a - b) -13 = (18a - 9b -13)(2a - b +1)
APPEARS IN
संबंधित प्रश्न
Get the algebraic expression in the following case using variables, constants and arithmetic operations.
Numbers x and y both squared and added.
Factorize : x2 + y - xy - x
Factorize the following expressions:
32a3 + 108b3
8x3 + 27y3 - 216z3 + 108xyz
8x3 -125y3 +180xy + 216
`2sqrt2a^3 + 16sqrt2b^3 + c^3 - 12abc`
The factors of x4 + x2 + 25 are
Which of the following expressions has the value 37?
In the formula, area of circle = πr2, the numerical constant of the expression πr2 is ______.
Will the value of 11x for x = –5 be greater than 11 or less than 11? Explain.
