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प्रश्न
Divide: 3y3 - 9ay2 - 6ab2y by -3y
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उत्तर
`(3y^3 - 9ay^2 - 6ab^2y)/(-3y)`
Write the division term by term:
`(3y^3)/(-3y) - (9ay^2)/(-3y) - (6ab^2y)/(-3y)`
Simplify each term
1. For `(3y^3)/(-3y): (3y^3)/(-3y) = -y^2`
2. For `(9ay^2)/(-3y): (9ay^2)/(-3y) = -3ay`
3. For `(6ab^2y)/(-3y) = -2ab^2`
Combine all the simplified terms:
−y2 + 3ay + 2ab2
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