Question

Divide: 3y³ - 9ay² - 6ab²y by -3y 

Answer 1

`(3y^3 - 9ay^2 - 6ab^2y)/(-3y)`

Write the division term by term:

`(3y^3)/(-3y) - (9ay^2)/(-3y) - (6ab^2y)/(-3y)`

Simplify each term

1. For `(3y^3)/(-3y): (3y^3)/(-3y) = -y^2`

2. For `(9ay^2)/(-3y): (9ay^2)/(-3y) = -3ay`

3. For `(6ab^2y)/(-3y) = -2ab^2`

Combine all the simplified terms:

−y² + 3ay + 2ab²