Advertisements
Advertisements
प्रश्न
Factorize a3 – 3a2b + 3ab2 – b3 + 8
Advertisements
उत्तर
a3 - 3a2b + 3ab2 - b3 + 8
= (a - b)3 + 8 [∵ a3 - b3 - 3a2b + 3ab2 = (a - b)3
= (a - b)3 + 23
= (a - b + 2)((a - b)2 - (a - b)2 + 22 ) [∵ a3 + b3 = (a + b)(a2 - ab + b2)]
= (a - b + 2)(a2 + b2 - 2ab - 2(a - b) + 4)
= (a - b + 2)(a2 + b2 - 2ab - 2a + 2b + 4)
∴ a3 - 3a2b + 3ab2 - b3 + 8 = (a - b + 2)(a2 + b2 - 2ab - 2a + 2b + 4)
APPEARS IN
संबंधित प्रश्न
Factorize: `a^2 x^2 + (ax^2 + 1)x + a`
Factorize a2 - b2 + 2bc - c2
Factorize the following expressions:
p3 + 27
Factorize the following expressions:
`x^3/216 - 8y^3`
Factorize the following expressions:
x4y4 - xy
Factorize 8a3 + 27b3 + 36a2b + 54ab2
The factors of 8a3 + b3 − 6ab + 1 are
The expression x4 + 4 can be factorized as
Rohan’s mother gave him ₹ 3xy2 and his father gave him ₹ 5(xy2 + 2). Out of this total money he spent ₹ (10 – 3xy2) on his birthday party. How much money is left with him?
Express the following properties with variables x, y and z.
Commutative property of addition
