Advertisements
Advertisements
प्रश्न
Factorize x3 - 2x2 y + 3xy2 - 6y3
Advertisements
उत्तर
Taking x2 common in (x3 - 2x2 y ) and +3y2 common in (3xy2 - 6y3)
= x2 ( x - 2 y ) + 3y2 ( x - 2 y )
= ( x - 2 y)(x2 + 3y2 )
∴ x3 - 2x2 y + 3xy2 - 6y3 = ( x - 2y )(x2 + 3y2 )
APPEARS IN
संबंधित प्रश्न
Factorize `21x^2 - 2x + 1/21`
Factorize the following expressions:
p3 + 27
Factorize the following expressions:
x3 + 6x2 +12x +16
Factorize 125x3 - 27 y3 - 225x2 y +135xy2
8x3 + 27y3 - 216z3 + 108xyz
`2sqrt2a^3 + 3sqrt3b^3 + c^3 - 3 sqrt6abc`
Divide: p2 + 4p + 4 by p + 2
In the formula, area of circle = πr2, the numerical constant of the expression πr2 is ______.
In the expression 2πr, the algebraic variable is ______.
A school has a rectangular playground with length x and breadth y and a square lawn with side x as shown in the figure given below. What is the total perimeter of both of them combined together?
