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प्रश्न
Factorize x3 - 2x2 y + 3xy2 - 6y3
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उत्तर
Taking x2 common in (x3 - 2x2 y ) and +3y2 common in (3xy2 - 6y3)
= x2 ( x - 2 y ) + 3y2 ( x - 2 y )
= ( x - 2 y)(x2 + 3y2 )
∴ x3 - 2x2 y + 3xy2 - 6y3 = ( x - 2y )(x2 + 3y2 )
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