हिंदी

If a pair of opposite sides of a cyclic quadrilateral are equal, prove that its diagonals are also equal.

Advertisements
Advertisements

प्रश्न

If a pair of opposite sides of a cyclic quadrilateral are equal, prove that its diagonals are also equal.

योग
Advertisements

उत्तर

Given: Let ABCD be a cyclic quadrilateral and AD = BC.

Join AC and BD.

To prove: AC = BD

Proof: In ΔAOD and ΔBOC,

∠OAD = ∠OBC and ∠ODA = ∠OCB  ...[Since, same segments subtends equal angle to the circle]

AB = BC  ...[Given]

ΔAOD = ΔBOC  ...[By ASA congruence rule]

Adding is DOC on both sides, we get

ΔAOD + ΔDOC ≅ ΔBOC + ΔDOC

⇒ ΔADC ≅ ΔBCD

AC = BD  ...[By CPCT]

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 10: Circles - Exercise 10.3 [पृष्ठ १०४]

APPEARS IN

एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 9
अध्याय 10 Circles
Exercise 10.3 | Q 12. | पृष्ठ १०४

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

If circles are drawn taking two sides of a triangle as diameters, prove that the point of intersection of these circles lie on the third side.


Prove that the circle drawn with any side of a rhombus as diameter passes through the point of intersection of its diagonals.


ABCD is a parallelogram. The circle through A, B and C intersect CD (produced if necessary) at E. Prove that AE = AD.


In any triangle ABC, if the angle bisector of ∠A and perpendicular bisector of BC intersect, prove that they intersect on the circumcircle of the triangle ABC.


Bisectors of angles A, B and C of a triangle ABC intersect its circumcircle at D, E and F respectively. Prove that the angles of the triangle DEF are 90°-A, 90° − `1/2 A, 90° − 1/2 B, 90° − 1/2` C.


In the figure, `square`ABCD is a cyclic quadrilateral. Seg AB is a diameter. If ∠ ADC = 120˚, complete the following activity to find measure of ∠ BAC.

`square` ABCD is a cyclic quadrilateral.
∴ ∠ ADC + ∠ ABC = 180°
∴ 120˚ + ∠ ABC = 180°
∴ ∠ ABC = ______
But ∠ ACB = ______  .......(angle in semicircle)

In Δ ABC,
∠ BAC + ∠ ACB + ∠ ABC = 180°
∴ ∠BAC + ______ = 180°
∴ ∠ BAC = ______


Prove that the circles described on the four sides of a rhombus as diameters, pass through the point of intersection of its diagonals. 


ABCD is a cyclic quadrilateral in which BA and CD when produced meet in E and EA = ED. Prove that  EB = EC


ABCD is a cyclic quadrilateral such that AB is a diameter of the circle circumscribing it and ∠ADC = 140º, then ∠BAC is equal to ______.


The three angles of a quadrilateral are 100°, 60°, 70°. Find the fourth angle.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×