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सी.आई.एस.सी.ई.आईसीएसई ICSE Class 8

From the following figure find; x ∠ABC ∠ACD

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प्रश्न

From the following figure find;

  1. x
  2. ∠ABC
  3. ∠ACD
योग
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उत्तर

(i) In Quadrilateral ABCD,

x + 4x + 3x + 4x + 48° = 360°

12x = 360° – 48°

12x = 312

x = `312/12` = 26°

(ii) ∠ABC = 4x

4 × 26 = 104°

(iii) ∠ACD = 180° − 4x − 48°

= 180° − 4 × 26° − 48°

= 180° − 104° − 48°

= 180° − 152° = 28°

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 16: Understanding Shapes - Exercise 16 (C) [पृष्ठ १८७]

APPEARS IN

सेलिना Concise Mathematics [English] Class 8 ICSE
अध्याय 16 Understanding Shapes
Exercise 16 (C) | Q 6 | पृष्ठ १८७
सेलिना Concise Mathematics [English] Class 6 ICSE
अध्याय 16 Quadrilateral
Exercise 27 (A) | Q 6

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