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For the given capacitor configuration (a) Find the charges on each capacitor (b) potential difference across them (c) energy stored in each capacitor.

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प्रश्न

For the given capacitor configuration

  1. Find the charges on each capacitor
  2. potential difference across them
  3. energy stored in each capacitor.

दीर्घउत्तर
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उत्तर

Capacitor b and c in parallel combination

Cp = Cb + Cc = (6 + 2) μF = 8 μF

Capacitor a, cp and d are in series combination, so the resulatant copacitance

`1/"C"_"s" = 1/"C"_"a" + 1/"C"_"cp" + 1/"C"_"d"`

`= 1/8 + 1/8 + 1/8 = 3/8`

`"C"_"s" = 8/3` μF

  1. Charge on each capacitor,
    Charge on capacitor a, Qa = Cs V = `8/3 xx 9`
    Qa = 24 μC
    Charge on capacitor, d, Qd = Cs V = `8/3 xx 9`
    Qd = 24 μC
    Capacitor b and c in parallel
    Charge on capacitor, b, Qb = `6/3 xx 9` = 18
    Qb = 18 μC
    Charge on capacitor, c, Qc = `2/3 xx 9` = 6
    Qc = 6 μC
  2. Potential difference across each capacitor, V = `"q"/"c"`
    Capacitor Ca, Va = `"q"_"a"/"C"_"a" = (24 xx 10^6)/(8 xx 10^6)` = 3 V
    Capacitor Cb, Vb = `"q"_"b"/"C"_"b" = (18 xx 10^6)/(6 xx 10^6)` = 3 V
    Capacitor Cc, Vc = `"q"_"c"/"C"_"c" = (6 xx 10^6)/(2 xx 10^6)` = 3 V
    Capacitor Cd, Vd = `"q"_"d"/"C"_"d" = (24 xx 10^6)/(8 xx 10^6)` = 3 V
  3. Energy stores in a capacitor, U = `1/2` CV2
    Energy in capacitor Ca, Ua = `1/2 "C"_"a" "V"_"a"^2 = 1/2 xx 8 xx 10^-6 xx (3)^2`
    Ua = 36 μJ
    Capacitor Cb, Ub = `1/2 "C"_"b"  "V"_"b"^2 = 1/2 xx 6 xx 10^-6 xx (3)^2`
    Ua = 27 μJ
    Cc, Uc = `1/2 "C"_"c"  "V"_"c"^2 = 1/2 xx 2 xx 10^-6 xx (3)^2`
    Ua = 9 μJ
    Cd, Ud = `1/2 "C"_"d"  "V"_"d"^2 = 1/2 xx 8 xx 10^-6 xx (3)^2`

    Ua = 36 μJ

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अध्याय 1: Electrostatics - Evaluation [पृष्ठ ७८]

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सामाचीर कलवी Physics - Volume 1 and 2 [English] Class 12 TN Board
अध्याय 1 Electrostatics
Evaluation | Q 14. | पृष्ठ ७८

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