Advertisements
Advertisements
प्रश्न
For a reaction : 
(i) Write the order and molecularity of this reaction.
(ii) Write the unit of k.
Advertisements
उत्तर
(i) This reaction is catalysed by Pt at high pressure. So, it is a zero-order reaction with molecularity 2.
(ii) The rate law expression for this reaction is
Rate = k
Hence, the unit of k is mol L−1 s−1.
APPEARS IN
संबंधित प्रश्न
A → B is a first order reaction with rate 6.6 × 10-5m-s-1. When [A] is 0.6m, rate constant of the reaction is
- 1.1 × 10-5s-1
- 1.1 × 10-4s-1
- 9 × 10-5s-1
- 9 × 10-4s-1
For a reaction A + B ⟶ P, the rate is given by
Rate = k [A] [B]2
How is the rate of reaction affected if the concentration of B is doubled?
Mention the factors that affect the rate of a chemical reaction.
How does calcination differ from roasting?
The value of rate constant of a pseudo first order reaction ______.
Why can we not determine the order of a reaction by taking into consideration the balanced chemical equation?
Assertion: Order of the reaction can be zero or fractional.
Reason: We cannot determine order from balanced chemical equation.
A catalyst in a reaction changes which of the following?
In the presence of a catalyst, the heat evolved or absorbed during the reaction.
On heating compound (A) gives a gas (B) which is constituent of air. The gas when treated with H2 in the presence of catalyst gives another gas (C) which is basic in nature, (A) should not be ______.
