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Find the ratio in which point P(k, 7) divides the segment joining A(8, 9) and B(1, 2). Also find k.

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प्रश्न

Find the ratio in which point P(k, 7) divides the segment joining A(8, 9) and B(1, 2). Also find k.

योग
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उत्तर

Let A(x1, y1), B(x2, y2) and P(x, y) be the given points.

Here, x1 = 8, y1 = 9, x2 = 1, y2 = 2, x = k, y = 7

∴ By section formula,

`y = (my_2 + ny_1)/(m + n)`

∴ `7 = (2m  +  9n)/(m + n)`

∴ 7(m + n) = 2m + 9n

∴  7m + 7n = 2m + 9n

∴ 5m = 2n

∴ `m/n = 2/5`

m : n = 2 : 5

`x = (mx_2 + nx_1)/(m + n)`

∴ `k = (2(1) + 5(8))/(2 + 5)`

∴ `k = (2 + 40)/(7)`

∴ `k = (42)/(7)`

∴ k = 6

∴ Point P divides seg AB in the ratio 2 : 5, and the value of k is 6.

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अध्याय 5: Co-ordinate Geometry - Practice Set 5.2 [पृष्ठ ११५]

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बालभारती Geometry Mathematics 2 [English] Standard 10 Maharashtra State Board
अध्याय 5 Co-ordinate Geometry
Practice Set 5.2 | Q 5 | पृष्ठ ११५

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