हिंदी

Find the number of years for which an annuity of ₹500 is paid at the end of every year, if the accumulated amount works out to be ₹1,655 when interest is compounded annually at 10% p.a.

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प्रश्न

Find the number of years for which an annuity of ₹500 is paid at the end of every year, if the accumulated amount works out to be ₹1,655 when interest is compounded annually at 10% p.a.

योग
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उत्तर

Given, C = ₹500, A = ₹1,655, r = 10% p.a.

∴ i = `"r"/(100) = (10)/(100)` = 0.1

Now,  A = `"C"/"i"[(1 + "i")^"n" - 1]`

∴ 1,655 = `(500)/(0.1)[(1 + 0.1)^"n" - 1]`

∴ `((1,655)(0.1))/(500)` = (1.1)n – 1

∴ 0.331= (1.1)n – 1
∴ (1.1)n  = 1 + 0.331
∴ (1.1)n  = 1.331
∴ (1.1)n  = (1.1)3
∴ n = 3
∴ The annuity is paid for 3 years.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 2: Insurance and Annuity - Exercise 2.2 [पृष्ठ २८]

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बालभारती Mathematics and Statistics 2 (Commerce) [English] Standard 12 Maharashtra State Board
अध्याय 2 Insurance and Annuity
Exercise 2.2 | Q 1.1 | पृष्ठ २८

संबंधित प्रश्न

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The future amount, A = ₹ 10,00,000

Period, n = 20, r = 5%, (1.025)20 = 1.675

A = `"C"/"I" [(1 + "i")^"n" - 1]`

I = `5/200` = `square` as interest is calculated semi-annually

A = 10,00,000 = `"C"/"I" [(1 + "i")^"n" - 1]`

10,00,000 = `"C"/0.025 [(1 + 0.025)^square - 1]`

= `"C"/0.025 [1.675 - 1]`

10,00,000 = `("C" xx 0.675)/0.025`

C = ₹ `square`


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