हिंदी

Fill in the blank : If payments of an annuity fall due at the end of every period, the series is called annuity __________.

Advertisements
Advertisements

प्रश्न

Fill in the blank :

If payments of an annuity fall due at the end of every period, the series is called annuity __________.

रिक्त स्थान भरें
Advertisements

उत्तर

If payments of an annuity fall due at the end of every period, the series is called annuity immediate.

shaalaa.com
Annuity
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 2: Insurance and Annuity - Miscellaneous Exercise 2 [पृष्ठ ३०]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Commerce) [English] Standard 12 Maharashtra State Board
अध्याय 2 Insurance and Annuity
Miscellaneous Exercise 2 | Q 2.1 | पृष्ठ ३०

संबंधित प्रश्न

A person wants to create a fund of ₹ 6,96,150 after 4 years at the time of his retirement. He decides to invest a fixed amount at the end of every year in a bank that offers him interest of 10% p.a. compounded annually. What amount should he invest every year? [Given (1.1)4 = 1.4641]


Find the number of years for which an annuity of ₹500 is paid at the end of every year, if the accumulated amount works out to be ₹1,655 when interest is compounded annually at 10% p.a.


A person plans to put ₹400 at the beginning of each year for 2 years in a deposit that gives interest at 2% p.a. compounded annually. Find the amount that will be accumulated at the end of 2 years.


Find the present value of an annuity due of ₹ 600 to be paid quarterly at 32% p.a. compounded quarterly. [Given (1.08)−4 = 0.7350]


For an annuity immediate paid for 3 years with interest compounded at 10% p.a., the present value is ₹24,000. What will be the accumulated value after 3 years? [Given (1.1)3 = 1.331]


______ is a series of constant cash flows over a limited period of time.


Fill in the blank :

The intervening time between payment of two successive installments is called as ___________.


Fill in the blank :

If payments of an annuity fall due at the beginning of every period, the series is called annuity __________.


State whether the following is True or False :

Annuity contingent begins and ends on certain fixed dates.


State whether the following is True or False :

The present value of an annuity is the sum of the present value of all installments.


Solve the following :

A shopkeeper insures his shop and godown valued at ₹5,00,000 and ₹10,00,000 respectively for 80 % of their values. If the rate of premium is 8 %, find the total annual premium.


Solve the following :

Find the least number of years for which an annuity of ₹3,000 per annum must run in order that its amount exceeds ₹60,000 at 10% compounded annually. [(1.1)11 = 2.8531, (1.1)12 = 3.1384]


Solve the following :

Find the present value of an annuity immediate of ₹20,000 per annum for 3 years at 10% p.a. compounded annually. [(1.1)–3 = 0.7513]


Solve the following :

After how many years would an annuity due of ₹3,000 p.a. accumulated ₹19,324.80 at 20% p. a. compounded yearly? [Given (1.2)4 = 2.0736]


Multiple choice questions:

In an ordinary annuity, payments or receipts occur at ______


Multiple choice questions:  

In annuity calculations, the interest is usually taken as ______


State whether the following statement is True or False:

Annuity contingent begins and ends on certain fixed dates


If for an immediate annuity r = 10% p.a., P = ₹ 12,679.46 and A = ₹ 18,564, then the amount of each annuity paid is ______


If payments of an annuity fall due at the beginning of every period, the series is called annuity ______


The intervening time between payment of two successive installments is called as ______


Find the amount of an ordinary annuity if a payment of ₹ 500 is made at the end of every quarter for 5 years at the rate of 12% per annum compounded quarterly. [Given (1.03)20 = 1.8061]


For an annuity due, C = ₹ 2000, rate = 16% p.a. compounded quarterly for 1 year

∴ Rate of interest per quarter = `square/4` = 4

⇒ r = 4%

⇒ i = `square/100 = 4/100` = 0.04

n = Number of quarters

= 4 × 1

= `square`

⇒ P' = `(C(1 + i))/i [1 - (1 + i)^-n]`

⇒ P' = `(square(1 + square))/0.04 [1 - (square + 0.04)^-square]`

= `(2000(square))/square [1 - (square)^-4]`

= 50,000`(square)`[1 – 0.8548]

= ₹ 7,550.40


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×