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Solve the following : A company decides to set aside a certain amount at the end of every year to create a sinking fund that should amount to ₹9,28,200 in 4 years at 10% - Mathematics and Statistics

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प्रश्न

Solve the following :

A company decides to set aside a certain amount at the end of every year to create a sinking fund that should amount to ₹9,28,200 in 4 years at 10% p.a. Find the amount to be set aside every year. [(1.1)4 = 1.4641]

योग
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उत्तर

Given, A = ₹9,28,200, n = 4 years, r = 10% p.a, i = `"r"/(100) = (10)/(100)` = 0.1

Now, A = `"C"/"i"[(1 + "i")^"n" - 1]`

∴ 9,28,200 = `"C"/(0.1)[(1 + 0.1)^4 - 1]`

∴ 9,28,200 x 0.1 = C[(1.1)4 – 1]
∴ 92,820 = C[1.4641 – 1]
∴ 92,820 = C(0.4641)
∴ C = `(92,820)/(0.4641)`
∴ C = ₹2,00,000
∴ The amount to be set aside each year is ₹2,00,000.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 2: Insurance and Annuity - Miscellaneous Exercise 2 [पृष्ठ ३२]

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बालभारती Mathematics and Statistics 2 (Commerce) [English] Standard 12 Maharashtra State Board
अध्याय 2 Insurance and Annuity
Miscellaneous Exercise 2 | Q 4.21 | पृष्ठ ३२

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For annuity due,

C = ₹ 20,000, n = 3, I = 0.1, (1.1)–3 = 0.7513

Therefore, P = `square/0.1 xx [1 - (1 + 0.1)^square]`

= 2,00,000 [1 – 0.7513]

= ₹ `square`


The future amount, A = ₹ 10,00,000

Period, n = 20, r = 5%, (1.025)20 = 1.675

A = `"C"/"I" [(1 + "i")^"n" - 1]`

I = `5/200` = `square` as interest is calculated semi-annually

A = 10,00,000 = `"C"/"I" [(1 + "i")^"n" - 1]`

10,00,000 = `"C"/0.025 [(1 + 0.025)^square - 1]`

= `"C"/0.025 [1.675 - 1]`

10,00,000 = `("C" xx 0.675)/0.025`

C = ₹ `square`


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