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Find the equation of the parabola in the cases given below: Vertex (1, – 2) and Focus (4, – 2)

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प्रश्न

Find the equation of the parabola in the cases given below:

Vertex (1, – 2) and Focus (4, – 2)

योग
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उत्तर


In given data the parabola is open rightwards and symmetric about the line parallel to x-axis.

Equation of parabola

(y – k)2 = 4a(x – h)

Vertex (h, k) = (1, – 2)

(y + 2)2 = 4a(x – 1)

a = AS = 3

Equation of parabola

(y + 2)2 = 4(3)(x – 1)

(y + 2)2 = 12(x – 1)

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Two Dimensional Analytical Geometry-II - Exercise 5.2 [पृष्ठ १९६]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 12 TN Board
अध्याय 5 Two Dimensional Analytical Geometry-II
Exercise 5.2 | Q 1. (iii) | पृष्ठ १९६

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