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Find the mean, variance and standard deviation for the data:  227, 235, 255, 269, 292, 299, 312, 321, 333, 348. - Mathematics

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प्रश्न

Find the mean, variance and standard deviation for the data:

 227, 235, 255, 269, 292, 299, 312, 321, 333, 348.

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उत्तर

 227,235,255,269,292,299,312,321,333,348,

\[\text{ Mean } = \frac{227 + 235 + 255 + 269 + 292 + 299 + 312 + 321 + 333 + 348}{10}\]

\[ = \frac{2891}{10} = 289 . 1\]

\[x_i\]
\[\left( x_i - X \right) = \left( x_i - 289 . 1 \right)\]
\[\left( x_i - X \right)^2\]
227 − 62.1 3856.41
235 − 54.1 2926.81
255 − 34.1 1162.81
269 − 20.1 404.01
292 2.9 8.41
299 9.9 98.01
312 22.9 524.41
321 31.9 1017.61
333 43.9 1927.21
348 58.9 3469.21
   
\[\sum^{10}_{i = 1} \left( x_i - \bar{x} \right)^2 = 15394 . 9\]

n = 10

\[n = 10\]

\[ \therefore \text{ Variance }  \left( X \right) = \frac{\sum^{10}_{i = 1} \left( x_i - \bar{X} \right)^2}{n} \]

\[ = \frac{15394 . 9}{10} \]

\[ = 1539 . 49\]

\[\text{ Standard deviation } = \sqrt{\text{ Variance } \left( X \right)} \]

\[ = \sqrt{1539 . 49} \]

\[ = 39 . 24\]

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अध्याय 32: Statistics - Exercise 32.4 [पृष्ठ २८]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 32 Statistics
Exercise 32.4 | Q 1.3 | पृष्ठ २८

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