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Calculate the standard deviation for the following data:Class:0-3030-6060-9090-120120-150150-180180-210Frequency:9174382814424

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प्रश्न

Calculate the standard deviation for the following data:

Class: 0-30 30-60 60-90 90-120 120-150 150-180 180-210
Frequency: 9 17 43 82 81 44 24
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उत्तर

Class
 

\[f_i\]
Midpoint
\[\left( x_i \right)\]
 

\[y_i = \frac{x_i - 105}{30}\]
 

\[{y_i}^2\]
 

\[f_i y_i\]
 

\[f_i {y_i}^2\]
0−30 9 15 −3 9 −27 81
30−60 17 45 −2 4 −34 68
60−90 43 75 −1 1 −43 43
90−120 82 105 0 0 0 0
120−150 81 135 1 1 81 81
150−180 44 165 2 4 88 176
180−210 24 195 3 9 72 216
 
 

\[\sum f_i = N = 300\]
     
 

\[\sum f_i y_i = 137\]
 

 
\[\sum f_i {y_i}^2 = 665\]

 

 

Mean,

\[\bar{x} = a + h\left( \frac{1}{N}\Sigma f_i y_i \right) = 105 + 30\left( \frac{137}{300} \right) = 118 . 7\]
Variance:

\[\sigma^2 = \frac{h^2}{N^2}\left[ N\sum f_i {y_i}^2 - \left( \sum f_i y_i \right)^2 \right]\]

\[ = \frac{900}{90000}\left[ 300 \times 665 - 18769 \right]\]

\[ = \frac{1}{100}\left[ 199500 - 18769 \right]\]

\[ = \frac{180731}{100} = 1807 . 31\]

\[SD, \sigma = \sqrt{1807 . 31} = 42 . 51\]

 

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अध्याय 32: Statistics - Exercise 32.6 [पृष्ठ ४१]

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आर.डी. शर्मा Mathematics [English] Class 11
अध्याय 32 Statistics
Exercise 32.6 | Q 2 | पृष्ठ ४१

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