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Evaluate the following limit : limθ→0[sin(mθ)tan(nθ)]

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प्रश्न

Evaluate the following limit :

`lim_(theta -> 0) [(sin("m"theta))/(tan("n"theta))]`

योग
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उत्तर

`lim_(theta -> 0) (sin("m"theta))/(tan("n"theta))`

= `lim_(theta -> 0) (((sin("m"theta))/theta))/(((tan("m"theta))/theta))`  ...[∵ θ → 0, θ ≠ 0]

= `lim_(theta -> 0) ((sin("m"theta)/("m"theta)"h"))/((tan("n"theta)/("n"theta)))xx"m"/"n"`

= `"m"/"n" (lim_(theta -> 0) sin("m"theta)/("m"theta))/(lim_(theta -> 0) tan("n"theta)/("n"theta))`

= `"m"/"n"*1/1   ...[because theta -> 0","  therefore "m"theta","  "n"theta -> 0  "and" lim_(x -> theta) (sinx)/x = 1]`

= `"m"/"n"`

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अध्याय 7: Limits - Exercise 7.4 [पृष्ठ १४८]

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