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Each Capacitor Shown in Figure Has a Capacitance of 5⋅0 µF. the Emf of the Battery is 50 V. How Much Charge Will Flow Through Ab If the Switch S Is Closed? - Physics

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प्रश्न

Each capacitor shown in figure has a capacitance of 5⋅0 µF. The emf of the battery is 50 V. How much charge will flow through AB if the switch S is closed?

योग
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उत्तर

Initially, when the switch S is open, the equivalent capacitance is given by

`C_(eq) = (2CxxC)/(3C)`

`⇒ C_("eq") = 2/3 C = 2/3 xx 5.0  "uF"`

The Charge supplied by the battery is given by

`Q = C_(eq) xx V`

`⇒ Q = 2/3 xx (5.0  "uF") xx (50  "V")`

`⇒Q = 500/3  "uC"`

When the switch S is closed, no charge goes to the capacitor connected in parallel with the switch.

Thus, the equivalent capacitance is given by `C_(eq) = 2C = 2 xx 5.0 xx 10 = uF`

The charge supplied by the battery is given by

`Q = 10  "uF" xx 50 = 500  "uC"`

The initial charge stored in the shorted capacitor starts discharging."?

Hence, the charge that flows from A to B is given by

`Q_"net" = 500  "uC" - 500/3  "uC"`

`⇒ Q_"net" = 3.3 xx 10^-4 C`

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अध्याय 9: Capacitors - Exercises [पृष्ठ १६६]

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एचसी वर्मा Concepts of Physics Vol. 2 [English] Class 11 and 12
अध्याय 9 Capacitors
Exercises | Q 20 | पृष्ठ १६६

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