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प्रश्न
Draw a rectangle whose one side measures 8 cm and the length of each of whose diagonals is 10 cm.
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उत्तर
(i) Draw a side AB, equal to 8 cm.
(ii) With A as the centre, draw an arc of length 10 cm.
(iii) Draw\[\angle\]ABX = 90° which intersects the arc at C.
(iv)Draw\[\angle\]= 90° .
(v) With C as the centre, draw an arc of length 8 cm.
(vi) Join CD.
Thus, ABCD is the required rectangle.
संबंधित प्रश्न
Name the quadrilaterals whose diagonals are equal
Explain why a rectangle is a convex quadrilateral.
In the following figure, BDEF and DCEF are each a parallelogram. Is it true that BD = DC? Why or why not?
Diagonals of a parallelogram ABCD intersect at O. AL and CM are drawn perpendiculars to BD such that L and M lie on BD. Is AL = CM? Why or why not?
Which of the following statement is true for a rectangle?
Its diagonals are equal.
Which of the following statement are true for a square?
It has all its sides of equal length.
Prove that quadrilateral formed by the intersection of angle bisectors of all angles of a parallelogram is a rectangle.
Diagonals of a rectangle ABCD intersect at point O. If AC = 8 cm then find BO and if ∠CAD =35° then find ∠ACB.
Adjacent sides of a rectangle are 7 cm and 24 cm. Find the length of its diagonal.
Every parallelogram is a rectangle.
