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प्रश्न
Draw a ray diagram to show the formation of the image, when the object is placed between optical centre and principal focus of a convex lens.
State the signs and values of magnifications in the above mentioned case.
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उत्तर
When an object is placed between the optical center and principal focus of a convex lens:
Since the image formed is virtual and erect, the sign of magnification will be positive. Moreover, the image formed is magnified; therefore, the absolute value of magnification will be greater than one.
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संबंधित प्रश्न
Explain the following term related to spherical lenses:- optical centre
Explain the following term related to spherical lenses: focal length
Match the items given in Column I with one or more items of Column II.
| Column I | Column II | ||
| (a) | A plane mirror | (i) | Used as a magnifying glass. |
| (b) | A convex mirror | (ii) | Can form image of objects spread over a large area. |
| (c) | A convex lens | (iii) | Used by dentists to see enlarged image of teeth. |
| (d) | A concave mirror | (iv) | The image is always inverted and magnified. |
| (e) | A concave lens | (v) | The image is erect and of the same size as the object. |
| (vi) | The image is erect and smaller in size than the object. |
When a spherical mirror is held towards the sun and its sharp image is formed on a piece of a carbon paper for some time, a hole is burnt in the carbon paper.
What is the advantage of using a carbon paper rather than a white paper?
At what distance from a concave mirror of focal length 25 cm should an object be placed so that the size of image is equal to the size of the object.
AB is the object, A'B' is the image, and MM' is the position of the mirror. Complete the ray diagram showing the formation of the image and find the focal length of the mirror.
Define the term Principle focus.
Define focal length.
The radius of curvature of a spherical mirror is 18 cm. What is the focal length of this mirror?
