हिंदी

Differential Equation D Y D X = Y , Y ( 0 ) = 1 Function Y = Ex - Mathematics

Advertisements
Advertisements

प्रश्न

Differential equation \[\frac{dy}{dx} = y, y\left( 0 \right) = 1\]
Function y = ex

योग
Advertisements

उत्तर

We have,

\[y = e^x..........(1)\]

Differentiating both sides of (1) with respect to x, we get

\[\frac{dy}{dx} = e^x\]

⇒ \[\frac{dy}{dx} = y............\left[\text{Using (1)}\right]\]

It is the given differential equation.

Here, \[y = e^x\] satisfies the given differential equation; hence, it is a solution.

Also, when \[x = 0, y = e^0 = 1, i.e.,y(0) = 1 .\]

Hence, \[y = e^x\]  is the solution to the given initial value problem.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 22: Differential Equations - Exercise 22.04 [पृष्ठ २८]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 12
अध्याय 22 Differential Equations
Exercise 22.04 | Q 2 | पृष्ठ २८

वीडियो ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्न

Prove that:

`int_0^(2a)f(x)dx = int_0^af(x)dx + int_0^af(2a - x)dx`


\[\frac{d^3 x}{d t^3} + \frac{d^2 x}{d t^2} + \left( \frac{dx}{dt} \right)^2 = e^t\]

\[y\frac{d^2 x}{d y^2} = y^2 + 1\]

Differential equation \[\frac{d^2 y}{d x^2} - y = 0, y \left( 0 \right) = 2, y' \left( 0 \right) = 0\] Function y = ex + ex


Differential equation \[\frac{d^2 y}{d x^2} - 3\frac{dy}{dx} + 2y = 0, y \left( 0 \right) = 1, y' \left( 0 \right) = 3\] Function y = ex + e2x


\[\sqrt{a + x} dy + x\ dx = 0\]

\[\left( x - 1 \right)\frac{dy}{dx} = 2 xy\]

(1 + x2) dy = xy dx


tan y \[\frac{dy}{dx}\] = sin (x + y) + sin (x − y) 

 


\[\cos x \cos y\frac{dy}{dx} = - \sin x \sin y\]

Solve the following differential equation: 
(xy2 + 2x) dx + (x2 y + 2y) dy = 0


\[2x\frac{dy}{dx} = 3y, y\left( 1 \right) = 2\]

\[\frac{dy}{dx} = \left( x + y \right)^2\]

\[\frac{dy}{dx} = \frac{y^2 - x^2}{2xy}\]

\[x\frac{dy}{dx} = x + y\]

Solve the following differential equations:
\[\frac{dy}{dx} = \frac{y}{x}\left\{ \log y - \log x + 1 \right\}\]


\[\frac{dy}{dx} = \frac{y}{x} + \sin\left( \frac{y}{x} \right)\]

 

Solve the following initial value problem:-

\[\frac{dy}{dx} + 2y = e^{- 2x} \sin x, y\left( 0 \right) = 0\]


Solve the following initial value problem:-

\[\frac{dy}{dx} + 2y \tan x = \sin x; y = 0\text{ when }x = \frac{\pi}{3}\]


The decay rate of radium at any time t is proportional to its mass at that time. Find the time when the mass will be halved of its initial mass.


Find the equation of the curve passing through the point \[\left( 1, \frac{\pi}{4} \right)\]  and tangent at any point of which makes an angle tan−1  \[\left( \frac{y}{x} - \cos^2 \frac{y}{x} \right)\] with x-axis.


Find the equation of the curve which passes through the point (3, −4) and has the slope \[\frac{2y}{x}\]  at any point (x, y) on it.


At every point on a curve the slope is the sum of the abscissa and the product of the ordinate and the abscissa, and the curve passes through (0, 1). Find the equation of the curve.


The slope of a curve at each of its points is equal to the square of the abscissa of the point. Find the particular curve through the point (−1, 1).


Write the differential equation obtained by eliminating the arbitrary constant C in the equation x2 − y2 = C2.


Choose the correct option from the given alternatives:

The solution of `1/"x" * "dy"/"dx" = tan^-1 "x"` is


Find the differential equation whose general solution is

x3 + y3 = 35ax.


Solve the following differential equation.

`dy/dx = x^2 y + y`


Solve the following differential equation.

xdx + 2y dx = 0


Solve the following differential equation.

`(x + y) dy/dx = 1`


Solve the differential equation:

dr = a r dθ − θ dr


 `dy/dx = log x`


The solution of differential equation `x^2 ("d"^2y)/("d"x^2)` = 1 is ______


Solve the following differential equation

`y log y ("d"x)/("d"y) + x` = log y


Solve the following differential equation `("d"y)/("d"x)` = cos(x + y)

Solution: `("d"y)/("d"x)` = cos(x + y)    ......(1)

Put `square`

∴ `1 + ("d"y)/("d"x) = "dv"/("d"x)`

∴ `("d"y)/("d"x) = "dv"/("d"x) - 1`

∴ (1) becomes `"dv"/("d"x) - 1` = cos v

∴ `"dv"/("d"x)` = 1 + cos v

∴ `square` dv = dx

Integrating, we get

`int 1/(1 + cos "v")  "d"v = int  "d"x`

∴ `int 1/(2cos^2 ("v"/2))  "dv" = int  "d"x`

∴ `1/2 int square  "dv" = int  "d"x`

∴ `1/2* (tan("v"/2))/(1/2)` = x + c

∴ `square` = x + c


Solve the differential equation `"dy"/"dx" + 2xy` = y


There are n students in a school. If r % among the students are 12 years or younger, which of the following expressions represents the number of students who are older than 12?


The value of `dy/dx` if y = |x – 1| + |x – 4| at x = 3 is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×