English

Differential Equation D Y D X = Y , Y ( 0 ) = 1 Function Y = Ex - Mathematics

Advertisements
Advertisements

Question

Differential equation \[\frac{dy}{dx} = y, y\left( 0 \right) = 1\]
Function y = ex

Sum
Advertisements

Solution

We have,

\[y = e^x..........(1)\]

Differentiating both sides of (1) with respect to x, we get

\[\frac{dy}{dx} = e^x\]

⇒ \[\frac{dy}{dx} = y............\left[\text{Using (1)}\right]\]

It is the given differential equation.

Here, \[y = e^x\] satisfies the given differential equation; hence, it is a solution.

Also, when \[x = 0, y = e^0 = 1, i.e.,y(0) = 1 .\]

Hence, \[y = e^x\]  is the solution to the given initial value problem.

shaalaa.com
  Is there an error in this question or solution?
Chapter 22: Differential Equations - Exercise 22.04 [Page 28]

APPEARS IN

RD Sharma Mathematics [English] Class 12
Chapter 22 Differential Equations
Exercise 22.04 | Q 2 | Page 28

Video TutorialsVIEW ALL [2]

RELATED QUESTIONS

\[\frac{d^2 y}{d x^2} + \left( \frac{dy}{dx} \right)^2 + xy = 0\]

Form the differential equation representing the family of ellipses having centre at the origin and foci on x-axis.


Verify that y = 4 sin 3x is a solution of the differential equation \[\frac{d^2 y}{d x^2} + 9y = 0\]


Show that Ax2 + By2 = 1 is a solution of the differential equation x \[\left\{ y\frac{d^2 y}{d x^2} + \left( \frac{dy}{dx} \right)^2 \right\} = y\frac{dy}{dx}\]

 


For the following differential equation verify that the accompanying function is a solution:

Differential equation Function
\[x\frac{dy}{dx} + y = y^2\]
\[y = \frac{a}{x + a}\]

\[\frac{dy}{dx} = \tan^{- 1} x\]


\[\frac{dy}{dx} = x^5 \tan^{- 1} \left( x^3 \right)\]

\[\sin\left( \frac{dy}{dx} \right) = k ; y\left( 0 \right) = 1\]

\[x\frac{dy}{dx} + 1 = 0 ; y \left( - 1 \right) = 0\]

\[\frac{dy}{dx} + \frac{1 + y^2}{y} = 0\]

Solve the differential equation \[\frac{dy}{dx} = e^{x + y} + x^2 e^y\].

xy dy = (y − 1) (x + 1) dx


\[\sqrt{1 + x^2} dy + \sqrt{1 + y^2} dx = 0\]

\[\frac{dy}{dx} = y \tan 2x, y\left( 0 \right) = 2\] 

\[\frac{dy}{dx} = 2 e^x y^3 , y\left( 0 \right) = \frac{1}{2}\]

\[\frac{dy}{dx} = y \sin 2x, y\left( 0 \right) = 1\]

\[\frac{dy}{dx} = 2xy, y\left( 0 \right) = 1\]

\[\left( x + y \right)^2 \frac{dy}{dx} = 1\]

\[\frac{dy}{dx} = \frac{y - x}{y + x}\]

\[\frac{dy}{dx} = \frac{y}{x} - \sqrt{\frac{y^2}{x^2} - 1}\]

\[x\frac{dy}{dx} = y - x \cos^2 \left( \frac{y}{x} \right)\]

Solve the following initial value problem:-

\[y' + y = e^x , y\left( 0 \right) = \frac{1}{2}\]


Solve the following initial value problem:-

\[\frac{dy}{dx} + 2y \tan x = \sin x; y = 0\text{ when }x = \frac{\pi}{3}\]


The surface area of a balloon being inflated, changes at a rate proportional to time t. If initially its radius is 1 unit and after 3 seconds it is 2 units, find the radius after time t.


If the interest is compounded continuously at 6% per annum, how much worth Rs 1000 will be after 10 years? How long will it take to double Rs 1000?


Find the equation of the curve that passes through the point (0, a) and is such that at any point (x, y) on it, the product of its slope and the ordinate is equal to the abscissa.


Integrating factor of the differential equation cos \[x\frac{dy}{dx} + y\] sin x = 1, is


The differential equation \[x\frac{dy}{dx} - y = x^2\], has the general solution


The differential equation
\[\frac{dy}{dx} + Py = Q y^n , n > 2\] can be reduced to linear form by substituting


Verify that the function y = e−3x is a solution of the differential equation \[\frac{d^2 y}{d x^2} + \frac{dy}{dx} - 6y = 0.\]


Form the differential equation of the family of circles having centre on y-axis and radius 3 unit.


The price of six different commodities for years 2009 and year 2011 are as follows: 

Commodities A B C D E F

Price in 2009 (₹)

35 80 25 30 80 x
Price in 2011 (₹) 50 y 45 70 120 105

The Index number for the year 2011 taking 2009 as the base year for the above data was calculated to be 125. Find the values of x andy if the total price in 2009 is ₹ 360.


Find the particular solution of the differential equation `"dy"/"dx" = "xy"/("x"^2+"y"^2),`given that y = 1 when x = 0


In the following example, verify that the given function is a solution of the corresponding differential equation.

Solution D.E.
xy = log y + k y' (1 - xy) = y2

For the following differential equation find the particular solution.

`(x + 1) dy/dx − 1 = 2e^(−y)`,

when y = 0, x = 1


The integrating factor of the differential equation `dy/dx - y = x` is e−x.


Solve the differential equation:

dr = a r dθ − θ dr


The solution of differential equation `x^2 ("d"^2y)/("d"x^2)` = 1 is ______


The integrating factor of the differential equation `"dy"/"dx" (x log x) + y` = 2logx is ______.


Integrating factor of the differential equation `x "dy"/"dx" - y` = sinx is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×