हिंदी

Solve the differential equation:edydx=x - Mathematics and Statistics

Advertisements
Advertisements

प्रश्न

Solve the differential equation:

`e^(dy/dx) = x`

योग
Advertisements

उत्तर

`e^(dy/dx) = x`

∴ `dy/dx = log x`

∴ dy = log x dx

Integrating on both sides, we get

`int dy = int (logx)1 dx`

∴ `y = log x int1dx - int [ d/dx(logx)int1dx] dx`

= `x log x -int 1/x. x dx`

= `x log x -int dx`

∴ y = x log x - x + c

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 8: Differential Equation and Applications - Miscellaneous Exercise 8 [पृष्ठ १७२]

APPEARS IN

बालभारती Mathematics and Statistics 1 (Commerce) [English] Standard 12 Maharashtra State Board
अध्याय 8 Differential Equation and Applications
Miscellaneous Exercise 8 | Q 4.03 | पृष्ठ १७२

संबंधित प्रश्न

Prove that:

`int_0^(2a)f(x)dx = int_0^af(x)dx + int_0^af(2a - x)dx`


Find the differential equation of all the parabolas with latus rectum '4a' and whose axes are parallel to x-axis.


Verify that y = 4 sin 3x is a solution of the differential equation \[\frac{d^2 y}{d x^2} + 9y = 0\]


Show that y = AeBx is a solution of the differential equation

\[\frac{d^2 y}{d x^2} = \frac{1}{y} \left( \frac{dy}{dx} \right)^2\]

For the following differential equation verify that the accompanying function is a solution:

Differential equation Function
\[x\frac{dy}{dx} = y\]
y = ax

\[\frac{dy}{dx} - x \sin^2 x = \frac{1}{x \log x}\]

\[\cos x\frac{dy}{dx} - \cos 2x = \cos 3x\]

(1 + x2) dy = xy dx


xy (y + 1) dy = (x2 + 1) dx


\[5\frac{dy}{dx} = e^x y^4\]

x cos y dy = (xex log x + ex) dx


\[x\frac{dy}{dx} + y = y^2\]

\[\frac{dy}{dx} + \frac{\cos x \sin y}{\cos y} = 0\]

\[\frac{dr}{dt} = - rt, r\left( 0 \right) = r_0\]

Solve the differential equation \[\frac{dy}{dx} = \frac{2x\left( \log x + 1 \right)}{\sin y + y \cos y}\], given that y = 0, when x = 1.


\[\frac{dy}{dx}\cos\left( x - y \right) = 1\]

\[x\frac{dy}{dx} = y - x \cos^2 \left( \frac{y}{x} \right)\]

Solve the following initial value problem:-
\[x\frac{dy}{dx} - y = \log x, y\left( 1 \right) = 0\]


Solve the following initial value problem:-
\[\tan x\left( \frac{dy}{dx} \right) = 2x\tan x + x^2 - y; \tan x \neq 0\] given that y = 0 when \[x = \frac{\pi}{2}\]


The rate of growth of a population is proportional to the number present. If the population of a city doubled in the past 25 years, and the present population is 100000, when will the city have a population of 500000?


Find the curve for which the intercept cut-off by a tangent on x-axis is equal to four times the ordinate of the point of contact.

 

Find the equation of the curve which passes through the point (1, 2) and the distance between the foot of the ordinate of the point of contact and the point of intersection of the tangent with x-axis is twice the abscissa of the point of contact.


The normal to a given curve at each point (x, y) on the curve passes through the point (3, 0). If the curve contains the point (3, 4), find its equation.


Radium decomposes at a rate proportional to the quantity of radium present. It is found that in 25 years, approximately 1.1% of a certain quantity of radium has decomposed. Determine approximately how long it will take for one-half of the original amount of  radium to decompose?


Show that all curves for which the slope at any point (x, y) on it is \[\frac{x^2 + y^2}{2xy}\]  are rectangular hyperbola.


The differential equation satisfied by ax2 + by2 = 1 is


Find the coordinates of the centre, foci and equation of directrix of the hyperbola x2 – 3y2 – 4x = 8.


In each of the following examples, verify that the given function is a solution of the corresponding differential equation.

Solution D.E.
y = ex  `dy/ dx= y`

Verify y = `a + b/x` is solution of `x(d^2y)/(dx^2) + 2 (dy)/(dx)` = 0

y = `a + b/x`

`(dy)/(dx) = square`

`(d^2y)/(dx^2) = square`

Consider `x(d^2y)/(dx^2) + 2(dy)/(dx)`

= `x square + 2 square`

= `square`

Hence y = `a + b/x` is solution of `square`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×