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Consider the Function F : R+ → [-9 , ∞ ]Given By F(X) = 5x2 + 6x - 9. Prove That F Is Invertible With F -1 (Y) = `(Sqrt(54 + 5y) -3)/5` [Cbse 2015] - Mathematics

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प्रश्न

Consider the function f : R→  [-9 , ∞ ]given by f(x) = 5x2 + 6x - 9. Prove that f is invertible with -1 (y) = `(sqrt(54 + 5y) -3)/5`             [CBSE 2015]

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उत्तर

We have ,

f (x) = 5x2+ 6x − 9

Let y = 5x2+ 6x − 9

` = 5 (x^2 + 6/5x - 9/5)`

` = 5(x^2 + 2 xx x xx 3/5 + 9 /25 - 9/25 - 9/5)`

`= (( x + 3/5)^2 - 9/25 - 9/25)`

`=(x+ 3/5)^2 - 9/5 - 9 `

`= 5 (x + 3/5)^2 - 54/5`

⇒ `y + 54/5 = 5 (x+3/5)^2`

⇒ `(5y + 54)/25  (x + 3/5)^2`

⇒ `sqrt (5y +54)/25 = x +3/5`

⇒ `x  = sqrt (5y +54)/5  - 3/5`

⇒ `x  = (sqrt (5y +54)-3)/5 `

Let g (y) =` (sqrt(5y +54) -3)/5`

Now, 

fog (y) = f (g (y)) 

= f `((sqrt (5y+54)-3)/5)`

= 5  `((sqrt (5y+54)-3)/5)^2 + 6 ((sqrt (5y+54)-3)/5) = - 9 `

`= 5 ((5y + 54 +9 - 6 sqrt (5y +54))/25) + ((6 sqrt(5y + 54) -18)/5) -9`

`= (5y + 63 - 6 sqrt (5y + 54))/5 +(6 sqrt (5y + 54)- 18)/5 -9`

=` (5y + 63 - 18 - 45) /5`

= y 

= IY, Identity function 

Also, gof (x) = g (f(x))

= g (5x2 + 6x - 9 )

`= (sqrt(5(5x^2 + 6x - 9)+ 54)-3)/5`

`= (sqrt(25x^2 + 30x - 45 +54) -3)/5`

`=(sqrt(25 x^2 + 30x + 9) -3)/5`

`= (sqrt((5x + 3)^2) - 3)/5`

`= (5x +3 -3)/5`

 = x

= IX , Identity function

So, f is invertible .

Also, `f^-1 (y) = g (y) = (sqrt(5y +54) -3)/5`

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अध्याय 2: Functions - Exercise 2.4 [पृष्ठ ६९]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 2 Functions
Exercise 2.4 | Q 14 | पृष्ठ ६९

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