Advertisements
Advertisements
प्रश्न
Consider a 10-cm long piece of a wire which carries a current of 10 A. Find the magnitude of the magnetic field due to the piece at a point which makes an equilateral triangle with the ends of the piece.
Advertisements
उत्तर
Let AB be the wire of length 10 cm and P be the required point.
Given:
Magnitude of current, i = 10 A
The angles made by points A and B with point P are
\[ = \frac{{10}^{- 7} \times 10}{5\sqrt{3} \times {10}^{- 2}}\left( \frac{1}{2} + \frac{1}{2} \right)\]
\[ = 11 . 54 \times {10}^{- 6} T\]
APPEARS IN
संबंधित प्रश्न
The figure shows three infinitely long straight parallel current carrying conductors. Find the
- magnitude and direction of the net magnetic field at point A lying on conductor 1,
- magnetic force on conductor 2.
Two infinitely large plane thin parallel sheets having surface charge densities σ1 and σ2 (σ1 > σ2) are shown in the figure. Write the magnitudes and directions of the net fields in the regions marked II and III.
Derive the expression for force per unit length between two long straight parallel current carrying conductors. Hence define one ampere.
A current of 10 A is established in a long wire along the positive z-axis. Find the magnetic field \[\vec{B}\] at the point (1 m, 0, 0).
A long, straight wire of radius r carries a current i and is placed horizontally in a uniform magnetic field B pointing vertically upward. The current is uniformly distributed over its cross section. (a) At what points will the resultant magnetic field have maximum magnitude? What will be the maximum magnitude? (b) What will be the minimum magnitude of the resultant magnetic field?
The magnetic field existing in a region is given by `vecB = B_0(1 + x/1)veck` . A square loop of edge l and carrying a current i, is placed with its edges parallel to the x−y axes. Find the magnitude of the net magnetic force experienced by the loop.
Two long, straight wires, each carrying a current of 5 A, are placed along the x- and y-axis respectively. The currents point along the positive directions of the axes. Find the magnetic fields at the points (a) (1 m, 1 m), (b) (−1 m, 1 m), (c) (−1 m, −1 m) and (d) (1 m, −1 m).
A long, straight wire carries a current i. Let B1 be the magnetic field at a point P at a distance d from the wire. Consider a section of length l of this wire such that the point P lies on a perpendicular bisector of the section B2 be the magnetic field at this point due to this second only. Find the value of d/l so that B2 differs from B1 by 1%.
According to Ampere's circuital law, ______.
A milli voltmeter of 25 milli volt range is to be converted into an ammeter of 25 ampere range. The value (in ohm) of necessary shunt will be ______.
The nature of parallel and anti-parallel currents are ______.
Equal currents are passing through two very long and straight parallel wires in the same direction. They will ______
Beams of electrons and protons move parallel to each other in the same direction. They ______.
Two long, straight, parallel conductors carry currents flowing in opposite directions (antiparallel currents). The magnetic force between them is:
Which set of conditions must be satisfied in the definition of the ampere?
The force per unit length between two long parallel current-carrying conductors carrying currents I₁ and I₂, separated by a perpendicular distance d, is given by:
If the current Ia in conductor a is doubled while Ib and the distance d remain unchanged, the force per unit length F/L between the conductors:
A wire carrying a current of 1 A flows East → West in a region where the horizontal component of Earth's magnetic field is B = 3.0 × 10⁻⁵ T directed South → North. The force per unit length on the wire is:
