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प्रश्न
Assertion (A): Pent- 1- ene and pent- 2- ene are position isomers.
Reason (R): Position isomers differ in the position of functional group or a substituent.
विकल्प
Both A and R are correct and R is the correct explanation of A.
Both A and R are correct but R is not the correct explanation of A.
Both A and R are not correct.
A is not correct but R is correct.
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उत्तर
Both A and R are correct and R is the correct explanation of A.
Explanation:
When two or more compounds differ in the position of substituent atom or functional group on the carbon skeleton, they are known as position isomers and this phenomenon is termed as position isomerism. Pent-2-ene and pent-l-ene are position isomers because they differ in the position of the double bond.
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संबंधित प्रश्न
Write IUPAC name of the product obtained by the ozonolysis of the following compound:
2-Ethylbut-1-ene
What effect does branching of an alkane chain has on its boiling point?
Find out the type of isomerism exhibited by the following pair.
\[\begin{array}{cc}
\ce{CH3 - CH - CH2 - CH3 and CH3 - CH2 - O - CH2 - CH3}\\|\phantom{...........................................}\\
\ce{OH}\phantom{.........................................}\end{array}\]
Find out the type of isomerism exhibited by the following pair.

Find out the type of isomerism exhibited by the following pair.

Choose the correct option.
Which type of isomerism is possible in CH3 CHCHCH3?
Molecular formula of the functional isomer of methyl formate is ____________.
What type(s) of isomerism is(are) shown by [Co(NH3)4Br2]Cl?
What is the relationship between the members of following pairs of structures? Are they structural or geometrical isomers or resonance contributors?

What is the relationship between the members of following pairs of structures? Are they structural or geometrical isomers or resonance contributors?
\[\begin{array}{cc}\ce{^+OH}\\||\\
\ce{H - C - OH}\end{array}\]
\[\begin{array}{cc}\ce{OH}\phantom{.}\\|\phantom{...}\\
\ce{H - C^+ - OH}\end{array}\]
In which of the following, functional group isomerism is not possible?
Which of the following pairs are position isomers?
| I. | \[\begin{array}{cc} \phantom{.......................}\ce{O}\\ \phantom{.......................}||\\ \ce{CH3 - CH2 - CH2 - CH2 - C - H} \end{array}\] |
| II. | \[\begin{array}{cc} \phantom{.................}\ce{O}\\ \phantom{.................}||\\ \ce{CH3 - CH2 - CH2 - C - H} \end{array}\] |
| III. | \[\begin{array}{cc} \ce{CH3 - CH2 - C - CH2 - CH3}\\ \phantom{}||\\ \phantom{}\ce{O} \end{array}\] |
| IV. | \[\begin{array}{cc} \ce{CH3 - CH - CH2 - C - H}\\ \phantom{...}|\phantom{............}||\phantom{}\\ \phantom{...}\ce{CH3}\phantom{.........}\ce{O}\phantom{} \end{array}\] |
(i) I and II
(ii) II and III
(iii) II and IV
(iv) III and IV
Which of the following pairs are not functional group isomers?
| I. | \[\begin{array}{cc} \phantom{.......................}\ce{O}\\ \phantom{.......................}||\\ \ce{CH3 - CH2 - CH2 - CH2 - C - H} \end{array}\] |
| II. | \[\begin{array}{cc} \phantom{.................}\ce{O}\\ \phantom{.................}||\\ \ce{CH3 - CH2 - CH2 - C - H} \end{array}\] |
| III. | \[\begin{array}{cc} \ce{CH3 - CH2 - C - CH2 - CH3}\\ \phantom{}||\\ \phantom{}\ce{O} \end{array}\] |
| IV. | \[\begin{array}{cc} \ce{CH3 - CH - CH2 - C - H}\\ \phantom{...}|\phantom{............}||\phantom{}\\ \phantom{...}\ce{CH3}\phantom{.........}\ce{O}\phantom{} \end{array}\] |
(i) II and III
(ii) II and IV
(iii) I and IV
(iv) I and II
Consider structures I to VII and answer the question:
| I. | CH3 – CH2 – CH2 – CH2 – OH |
| II. | \[\begin{array}{cc} \ce{CH3 - CH2 - CH - CH3}\\ \phantom{.....}|\\ \phantom{.......}\ce{OH} \end{array}\] |
| III. | \[\begin{array}{cc} \phantom{...}\ce{CH3}\\ \phantom{}|\\ \ce{CH3 - C - CH3}\\ \phantom{}|\\ \phantom{..}\ce{OH} \end{array}\] |
| IV. | \[\begin{array}{cc} \ce{CH3 - CH - CH2 - OH}\\ |\phantom{........}\\ \ce{CH3}\phantom{......} \end{array}\] |
| V. | CH3 – CH2 – O – CH2 – CH3 |
| VI. | CH3 – O – CH2 – CH2 – CH3 |
| VII. | \[\begin{array}{cc} \ce{CH3 - O - CH - CH3}\\ \phantom{...}|\\ \phantom{......}\ce{CH3} \end{array}\] |
Identify the pairs of compounds which are functional group isomers.
Consider structures I to VII and answer the question:
| I. | CH3 – CH2 – CH2 – CH2 – OH |
| II. | \[\begin{array}{cc} \ce{CH3 - CH2 - CH - CH3}\\ \phantom{.....}|\\ \phantom{.......}\ce{OH} \end{array}\] |
| III. | \[\begin{array}{cc} \phantom{...}\ce{CH3}\\ \phantom{}|\\ \ce{CH3 - C - CH3}\\ \phantom{}|\\ \phantom{..}\ce{OH} \end{array}\] |
| IV. | \[\begin{array}{cc} \ce{CH3 - CH - CH2 - OH}\\ |\phantom{........}\\ \ce{CH3}\phantom{......} \end{array}\] |
| V. | CH3 – CH2 – O – CH2 – CH3 |
| VI. | CH3 – O – CH2 – CH2 – CH3 |
| VII. | \[\begin{array}{cc} \ce{CH3 - O - CH - CH3}\\ \phantom{...}|\\ \phantom{......}\ce{CH3} \end{array}\] |
Identify the pairs of compounds that represents position isomerism.
Consider structures I to VII and answer the question:
| I. | CH3 – CH2 – CH2 – CH2 – OH |
| II. | \[\begin{array}{cc} \ce{CH3 - CH2 - CH - CH3}\\ \phantom{.....}|\\ \phantom{.......}\ce{OH} \end{array}\] |
| III. | \[\begin{array}{cc} \phantom{...}\ce{CH3}\\ \phantom{}|\\ \ce{CH3 - C - CH3}\\ \phantom{}|\\ \phantom{..}\ce{OH} \end{array}\] |
| IV. | \[\begin{array}{cc} \ce{CH3 - CH - CH2 - OH}\\ |\phantom{........}\\ \ce{CH3}\phantom{......} \end{array}\] |
| V. | CH3 – CH2 – O – CH2 – CH3 |
| VI. | CH3 – O – CH2 – CH2 – CH3 |
| VII. | \[\begin{array}{cc} \ce{CH3 - O - CH - CH3}\\ \phantom{...}|\\ \phantom{......}\ce{CH3} \end{array}\] |
Identify the pairs of compounds that represents chain isomerism.
Compounds with same molecular formula but differing in their structures are said to be structural isomers. What type of structural isomerism is shown by
CH3 – S – CH2 – CH2 – CH3
And
\[\begin{array}{cc}
\phantom{.....................}\ce{CH3}\\
\phantom{................}/\\
\phantom{}\ce{CH3 - S - CH}\\
\phantom{...............}\backslash\\
\phantom{....................}\ce{CH3}
\end{array}\]
The molecules having dipole moment are:
(i) 2,2-Dimethylpropane
(ii) trans-Pent-2-ene
(iii) cis-Hex-3-ene
(iv) 2, 2, 3, 3 - Tetramethylbutane.
Assertion (A): The compound cyclooctane has the following structural formula: ![]()
It is cyclic and has conjugated 8π-electron system but it is not an aromatic compound.
Reason (R): (4n + 2)π electrons rule does not hold good and ring is not planar.
Tautomerism is exhibited by ______.
Which of the following does NOT exhibit geometrical isomerism?
The compound which shows metamerism is ______
Which type of isomerism can not be shown by benzaldoxime?
Acetamide is isomer of ______.
Which one of the following pairs are called position isomers?
Which of the following pairs of compounds are positional isomers?
Which of the following reactions will not produce a racemic product?
The number of geometrical isomers from [Co(NH3)3(NO2)3] is ______.
The total number of possible isomers of the complex compound [CuII(NH3)4][PtIICl4] is ______.
