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Assertion (A): Pent- 1- ene and pent- 2- ene are position isomers. Reason (R): Position isomers differ in the position of functional group or a substituent.

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प्रश्न

Assertion (A): Pent- 1- ene and pent- 2- ene are position isomers.

Reason (R): Position isomers differ in the position of functional group or a substituent.

विकल्प

  • Both A and R are correct and R is the correct explanation of A.

  • Both A and R are correct but R is not the correct explanation of A.

  • Both A and R are not correct.

  • A is not correct but R is correct.

MCQ
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उत्तर

Both A and R are correct and R is the correct explanation of A.

Explanation:

When two or more compounds differ in the position of substituent atom or functional group on the carbon skeleton, they are known as position isomers and this phenomenon is termed as position isomerism. Pent-2-ene and pent-l-ene are position isomers because they differ in the position of the double bond. 

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अध्याय 12: Organic Chemistry Some Basic Principles and Techniques - Multiple Choice Questions (Type - I) [पृष्ठ १५५]

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एनसीईआरटी एक्झांप्लर Chemistry Exemplar [English] Class 11
अध्याय 12 Organic Chemistry Some Basic Principles and Techniques
Multiple Choice Questions (Type - I) | Q 57 | पृष्ठ १५५

संबंधित प्रश्न

Write IUPAC name of the product obtained by the ozonolysis of the following compound:

3,4-Dimethyl-hept-3-ene


Write IUPAC name of the product obtained by the ozonolysis of the following compound:

2-Ethylbut-1-ene 


What is the relationship between the members of following pairs of structures? Are they structural or geometrical isomers or resonance contributors?

\[\begin{array}{cc}
\ce{D}\phantom{......}\ce{H}\\
\backslash\phantom{......}/\\
\ce{C = C}\\
\phantom{...}/\phantom{......}\backslash\phantom{...}\\\ce{H}\phantom{.......}\ce{D}
\end{array}\]

\[\begin{array}{cc}
\ce{D}\phantom{......}\ce{D}\\
\backslash\phantom{......}/\\
\ce{C = C}\\
\phantom{...}/\phantom{......}\backslash\phantom{...}\\\ce{H}\phantom{.......}\ce{H}\end{array}\]


Find out the type of isomerism exhibited by the following pair.

CH3 – CH2 – NH – CH2 - CH3 and CH3 - NH - CH2 - CH2 - CH3


Find out the type of isomerism exhibited by the following pair.


Find out the type of isomerism exhibited by the following pair.


Molecular formula of the functional isomer of methyl formate is ____________.


What type(s) of isomerism is(are) shown by [Co(NH3)4Br2]Cl?


But-1-ene and But-2-ene are examples of ____________.


Which of the following is a functional isomer of pentan-2-ol?


The type of isomerism possible in 2-butene is ____________.


What is the relationship between the members of following pairs of structures? Are they structural or geometrical isomers or resonance contributors?


In which of the following, functional group isomerism is not possible?


Which of the following pairs are not functional group isomers?

I. \[\begin{array}{cc}
\phantom{.......................}\ce{O}\\
\phantom{.......................}||\\
\ce{CH3 - CH2 - CH2 - CH2 - C - H}
\end{array}\]
II. \[\begin{array}{cc}
\phantom{.................}\ce{O}\\
\phantom{.................}||\\
\ce{CH3 - CH2 - CH2 - C - H}
\end{array}\]
III. \[\begin{array}{cc}
\ce{CH3 - CH2 - C - CH2 - CH3}\\
\phantom{}||\\
\phantom{}\ce{O}
\end{array}\]
IV. \[\begin{array}{cc}
\ce{CH3 - CH - CH2 - C - H}\\
\phantom{...}|\phantom{............}||\phantom{}\\
\phantom{...}\ce{CH3}\phantom{.........}\ce{O}\phantom{}
\end{array}\]

(i) II and III

(ii) II and IV

(iii) I and IV

(iv) I and II


Consider structures I to VII and answer the question:

I. CH3 – CH2 – CH2 – CH2 – OH
II. \[\begin{array}{cc}
\ce{CH3 - CH2 - CH - CH3}\\
\phantom{.....}|\\
\phantom{.......}\ce{OH}
\end{array}\]
III. \[\begin{array}{cc}
\phantom{...}\ce{CH3}\\
\phantom{}|\\
\ce{CH3 - C - CH3}\\
\phantom{}|\\
\phantom{..}\ce{OH}
\end{array}\]
IV. \[\begin{array}{cc}
\ce{CH3 - CH - CH2 - OH}\\
|\phantom{........}\\
\ce{CH3}\phantom{......}
\end{array}\]
V. CH3 – CH2 – O – CH2 – CH3
VI. CH3 – O – CH2 – CH2 – CH3
VII. \[\begin{array}{cc}
\ce{CH3 - O - CH - CH3}\\
\phantom{...}|\\
\phantom{......}\ce{CH3}
\end{array}\]

Identify the pairs of compounds which are functional group isomers.


Consider structures I to VII and answer the question:

I. CH3 – CH2 – CH2 – CH2 – OH
II. \[\begin{array}{cc}
\ce{CH3 - CH2 - CH - CH3}\\
\phantom{.....}|\\
\phantom{.......}\ce{OH}
\end{array}\]
III. \[\begin{array}{cc}
\phantom{...}\ce{CH3}\\
\phantom{}|\\
\ce{CH3 - C - CH3}\\
\phantom{}|\\
\phantom{..}\ce{OH}
\end{array}\]
IV. \[\begin{array}{cc}
\ce{CH3 - CH - CH2 - OH}\\
|\phantom{........}\\
\ce{CH3}\phantom{......}
\end{array}\]
V. CH3 – CH2 – O – CH2 – CH3
VI. CH3 – O – CH2 – CH2 – CH3
VII. \[\begin{array}{cc}
\ce{CH3 - O - CH - CH3}\\
\phantom{...}|\\
\phantom{......}\ce{CH3}
\end{array}\]

Identify the pairs of compounds that represents position isomerism.


The molecules having dipole moment are:

(i) 2,2-Dimethylpropane

(ii) trans-Pent-2-ene

(iii) cis-Hex-3-ene

(iv) 2, 2, 3, 3 - Tetramethylbutane.


Assertion (A): The compound cyclooctane has the following structural formula:

It is cyclic and has conjugated 8π-electron system but it is not an aromatic compound.

Reason (R): (4n + 2)π electrons rule does not hold good and ring is not planar.


Which of the following does NOT exhibit geometrical isomerism? 


Ether and alcohol are ______.


Which type of isomerism can not be shown by benzaldoxime?


Acetamide is isomer of ______.


Which one of the following pairs are called position isomers?


How many structural isomers possible of the molecular formula C3H6O (excluding enol form)?


The number of acyclic structural isomers (including geometrical isomers) for pentene are ______.


Compound with molecular formula C3H6O can show ______.


Which of the following pairs of compounds are positional isomers?


The number of geometrical isomers from [Co(NH3)3(NO2)3] is ______.


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