Advertisements
Advertisements
प्रश्न
An electrical bulb is marked 200V, 100W. Calculate the electrical resistance of its filament. If five such
bulbs are connected in series to a 200V supply, how much current will flow through them?
Advertisements
उत्तर
Voltage V = 200 V, Power P = 100 W
∴ Electrical current = `P/V = 100/200 = 1/2` Amp
∴ Electrical resistance `R = V/I = 200/("I/2") `= 400 Ω
if five bulbs are connected in series to 200V
∴ Total resistance RT = 400 + 400 + 400 + 400 + 400 = 2000Ω
Current flowing thorugh a bulb `I = 200/2000 = 0.1 A `
APPEARS IN
संबंधित प्रश्न
Why are coils of electric toasters and electric irons made of an alloy rather than a pure metal?
Find the expression for the resistivity of a material and state the SI unit of resistivity.
Keeping the p.d. constant, the resistance of a circuit is halved. The current will become:
(a) one-fourth
(b) four time
(c) half
(d) double
The graph between V and I for a conductor is a straight line passing through the origin.
Which law is illustrated by such a graph?
The graph between V and I for a conductor is a straight line passing through the origin.
What should remain constant in a statement of this law?
Four resistances of 16 ohms each are connected in parallel. Four such combinations are connected in series. What is the total resistance?
State macroscopic form of Ohm’s law.
Two cells each of 5V are connected in series across an 8Ω resistor and three parallel resistors of 4Ω, 6Ω, and 12Ω. Draw a circuit diagram for the above arrangement. Calculate
- the current drawn from the cell
- current through each resistor
How is electric current related to the potential difference across the terminals of a conductor?
Draw a labelled circuit diagram to verify this relationship.
