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An Electric Heater Which is Connected to a 220 V Supply Line Has Two Resistance Coils A And B Of 24 ω Resistance Each. These Coils Can Be Used Separately (One at a Time), in Series Or in Parallel. Calculate the Current Drawn When: (A) Only One Coil A Is Used. (B) Coils A And B Are Used in Series. (C) Coils A And B Are Uses in Parallel.

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प्रश्न

An electric heater which is connected to a 220 V supply line has two resistance coils A and B of 24 Ω resistance each. These coils can be used separately (one at a time), in series or in parallel. Calculate the current drawn when:

(a) only one coil A is used.
(b) coils A and B are used in series.
(c) coils A and B are uses in parallel.

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उत्तर

(a) When only one coil, A is used:
V = IR
220 = 24 I
I = 9.2 A

(b) When coils, A and B are used in series:
Total resistance R = RA+ RB = 48 Ω
V = IR
220 = 48 I
I = 4.58 A

(c) When coils, A and B are used in parallel:
 1/R = 1/RA+ 1/RB
Here, RA = 24 Ω and RB = 24 Ω
 1/R = 1/24 + 1/24
or 1/R = 2/24
      R = 12 Ω
Total resistance of parallel combination, R = 12 Ω
Now, V = IR
220 = 12 I
I = 18.33 A

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अध्याय 4: Electricity - Exercise 5 [पृष्ठ २२९]

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लखमीर सिंग Physics Part 1 [English] Class 10
अध्याय 4 Electricity
Exercise 5 | Q 22. | पृष्ठ २२९

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