हिंदी

An alternating voltage of 220 V is applied across a device X. A current of 0.22 A flows in the circuit and it lags behind the applied voltage in phase by π/2 radian. When the same

Advertisements
Advertisements

प्रश्न

An alternating voltage of 220 V is applied across a device X. A current of 0.22 A flows in the circuit and it lags behind the applied voltage in phase by π/2 radian. When the same voltage is applied across another device Y, the current in the circuit remains the same and it is in phase with the applied voltage.

  1. Name the devices X and Y and,
  2. Calculate the current flowing in the circuit when the same voltage is applied across the series combination of X and Y.
संख्यात्मक
Advertisements

उत्तर

  1. X is a resistor and Y is the capacitor.

  2.  
    R = `V_{rms}/I_{rms} = 220/0.22 = 1000 Omega`
    R = XC = 1000Ω
    When R and C are in series.
    `I_{rms} = V_{rms}/Z = V_{rms}/sqrt(R^2 + (X_C)^2)`
    = `220/sqrt((1000)^2 + (1000)^2)`
    = `220/(1000 xx sqrt2)`
    `I_{rms} = 0.156` A
shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
2022-2023 (March) Delhi Set 1

वीडियो ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्न

The time constant of an LR circuit is 40 ms. The circuit is connected at t = 0 and the steady-state current is found to be 2.0 A. Find the current at (a) t = 10 ms (b) t = 20 ms, (c) t = 100 ms and (d) t = 1 s.


An inductor-coil of resistance 10 Ω and inductance 120 mH is connected across a battery of emf 6 V and internal resistance 2 Ω. Find the charge which flows through the inductor in (a) 10 ms, (b) 20 ms and (c) 100 ms after the connections are made.


The magnetic field at a point inside a 2.0 mH inductor-coil becomes 0.80 of its maximum value in 20 µs when the inductor is joined to a battery. Find the resistance of the circuit.


Use the expression for Lorentz force acting on the charge carriers of a conductor to obtain the expression for the induced emf across the conductor of length l moving with velocity v through a magnetic field B acting perpendicular to its length.


Using the phasor diagram, derive the expression for the current flowing in an ideal inductor connected to an a.c. source of voltage, v= vo sin ωt. Hence plot graphs showing the variation of (i) applied voltage and (ii) the current as a function of ωt.


Choose the correct answer from given options
The phase difference between the current and the voltage in series LCR circuit at resonance is


At resonant frequency the current amplitude in series LCR circuit is ______.


The resonant frequency of a RF oscillator is 1 MHz and its bandwidth is 10 kHz. The quality factor will be :


Draw the impedance triangle for a series LCR AC circuit and write the expressions for the impedance and the phase difference between the emf and the current.


To an ac power supply of 220 V at 50 Hz, a resistor of 20 Ω, a capacitor of reactance 25 Ω and an inductor of reactance 45 Ω are connected in series. The corresponding current in the circuit and the phase angle between the current and the voltage is respectively:


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×