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प्रश्न
ABCD is a trapezium. Prove that:
CD + DA + AB + BC > 2AC.
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उत्तर
In ΔABC, we have
AB + BC > AC ...(i)
In ΔACD, we have
AD + CD > AC ...(ii)
Adding (i) and (ii), we get
AB + BC + AD + CD > 2AC.
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