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A woman throws an object of mass 500 g with a speed of 25 ms1. What is the impulse imparted to the object?

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प्रश्न

A woman throws an object of mass 500 g with a speed of 25 ms1.

  1. What is the impulse imparted to the object?
  2. If the object hits a wall and rebounds with half the original speed, what is the change in momentum of the object?
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उत्तर

Mass of the object (m) = 500 g = 0.5 kg

Speed of the object (v) = 25 m/s

a. Impulse imparted to the object = Change in momentum

= mv – mu

= m(v – u)

= 0.5(25 – 0)

= 12.5 N-s 

b. Velocity of the object after rebounds

= `- 25/2` m/s

v' = – 12.5 m/s

∴ Change in momentum = m(v’ – v)

= 0.5 (– 12.5 – 25)

= – 18.75 N-s

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अध्याय 5: Laws of Motion - Exercises [पृष्ठ ३४]

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एनसीईआरटी एक्झांप्लर Physics [English] Class 11
अध्याय 5 Laws of Motion
Exercises | Q 5.24 | पृष्ठ ३४

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