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प्रश्न
A stone of mass 2 kg is whirled in a horizontal circle attached at the end of 1.5m long string. If the string makes an angle of 30° with vertical, compute its period. (g = 9.8 m/s2)
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उत्तर
Given: m = 2 kg
l = 1.5 m
Θ = 30°
g = 9.8 m/s2
To find: Period (T)
= antilog[0.3592]
∴ T = 2.2875 s
Period of revolution is 2.287 s
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