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A String is Wrapped Over the Edge of a Uniform Disc and the Free End is Fixed with the Ceiling. the Disc Moves Down, Unwinding the String. Find the Downward Acceleration of the Disc.

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प्रश्न

A string is wrapped over the edge of a uniform disc and the free end is fixed with the ceiling. The disc moves down, unwinding the string. Find the downward acceleration of the disc.

योग
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उत्तर

Let the radius of the disc be R.

Let the tension in the string be T.

Let the acceleration of the disc be a.

From the free body diagram, we have

\[mg - T = ma ........(1)\]

Torque about the centre of disc,

\[T \times R = I \times \alpha\]

\[\Rightarrow   T \times R = \frac{1}{2}m R^2  \times \frac{a}{R}\]

\[ \Rightarrow T = \frac{1}{2}ma ...........(2)\]

Putting this value in equation (1), we get

\[mg - \frac{1}{2}ma = ma\]

\[ \Rightarrow mg = \frac{3}{2}ma\]

\[ \Rightarrow a = \frac{2g}{3}\]

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अध्याय 10: Rotational Mechanics - Exercise [पृष्ठ २००]

APPEARS IN

एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
अध्याय 10 Rotational Mechanics
Exercise | Q 72 | पृष्ठ २००

संबंधित प्रश्न

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Answer in Brief:

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