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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

A spherical conductor of radius 12 cm has a charge of 1.6 × 10−7 C distributed uniformly on its surface. What is the electric field (a) inside the sphere (b) just outside the sphere

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प्रश्न

A spherical conductor of radius 12 cm has a charge of 1.6 × 10−7 C distributed uniformly on its surface. What is the electric field

  1. inside the sphere
  2. just outside the sphere
  3. at a point 18 cm from the centre of the sphere?
संख्यात्मक
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उत्तर

(a) Radius of the spherical conductor, r = 12 cm = 0.12 m

Charge is uniformly distributed over the conductor, q = 1.6 × 10−7 C

The electric field inside a spherical conductor is zero. This is because if a field is inside the conductor, then charges will move to neutralize it.

(b) Electric field E just outside the conductor is given by the relation,

`E = q/(4piε_0r^2)`

Where,

`ε_0` = Permittivity of free space

`1/(4piε_0) = 9 xx 10^9` N m2 C−2

∴ `E = (1.6 xx 10^-7 xx 9 xx 10^9)/(0.12)^2`

= `(14.4 xx 10^2)/0.0144`

= 1000 × 102

= 105 N C−1

Therefore, the electric field just outside the sphere is 105 N C−1.

(c) Electric field at a point 18 m from the centre of the sphere = E1

Distance of the point from the centre, d = 18 cm = 0.18 m

`E_1 = q/(4piε_0d^2)`

= `(9 xx 10^9 xx 1.6 xx 10^-7)/(18 xx 10^-2)^2`

= `(14.4 xx 10^2)/(324 xx 10^-4)`

= 0.044 × 106

= 4.4 × 104 N C−1

Therefore, the electric field at a point 18 cm from the centre of the sphere is 4.4 × 104 N C−1.

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अध्याय 2: Electrostatic Potential and Capacitance - EXERCISES [पृष्ठ ७९]

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एनसीईआरटी Physics Part I and II [English] Class 12
अध्याय 2 Electrostatic Potential and Capacitance
EXERCISES | Q 2.4 | पृष्ठ ७९
एनसीईआरटी Physics Part I and II [English] Class 12
अध्याय 2 Electrostatic Potential and Capacitance
Exercise | Q 2.4 | पृष्ठ ८६

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