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A reaction occurs in the following steps: Step 1: NOX2(g)+FX2⟶NOX2FX(g)+FX(g) (slow) Step 2: FX(g)+NOX2(g)⟶NOX2F (Fast)

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प्रश्न

A reaction occurs in the following steps:

Step 1: \[\ce{NO_{2(g)} + F_2 -> NO2F_{(g)} + F_{(g)}}\] (slow)

Step 2: \[\ce{F_{(g)} + NO_{2(g)} -> NO_2F}\] (Fast)

  1. Write the equation of overall reaction.
  2. Write the rate law.
  3. Identify reaction intermediate.
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उत्तर

  1. Overall reaction: \[\ce{2NO_{2(g)} + F_{2(g)} -> 2NO2F_{(g)}}\]
  2. Step 1 is slow. The rate law of the reaction is predicted from its stoichiometry. Thus, rate = k[NO2] [F2]
  3. F is produced in step 1 and consumed in step 2. Hence, F is the reaction intermediate.
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अध्याय 6: Chemical Kinetics - Short answer questions (Type- II)

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