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Answer the following in one or two sentences. For the reaction,What is the change in rate if concentrations of both reactants are doubled? - Chemistry

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प्रश्न

Answer the following in one or two sentences.

For the reaction,

\[\ce{CH3Br_{(aq)} + OH^-_{ (aq)} -> CH3OH^-_{ (aq)} + Br^-_{ (aq)}}\], rate law is rate = k`["CH"_3"Br"]["OH"^-]`

What is the change in rate if concentrations of both reactants are doubled?

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उत्तर

For the reaction

\[\ce{CH3Br_{(aq)} + Br^-_{ (aq)} -> CH3OH_{ (aq)} + Br^-_{ (aq)}}\]

Rate = k`["CH"_3"Br"]["OH"^-]`

If concentrations of `"CH"_3"Br"` and `"OH"^-` are doubled, rate will increase by a factor of 4.

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Rate of Reaction and Reactant Concentration
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अध्याय 6: Chemical Kinetics - Exercises [पृष्ठ १३६]

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बालभारती Chemistry [English] Standard 12 Maharashtra State Board
अध्याय 6 Chemical Kinetics
Exercises | Q 2. ii. b. | पृष्ठ १३६

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