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What is the half life of a first order reaction if time required to decrease concentration of reactant from 0.8 M to 0.2 M is 12 h?

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प्रश्न

What is the half life of a first order reaction if time required to decrease concentration of reactant from 0.8 M to 0.2 M is 12 h?

विकल्प

  • 12 h

  • 3 h

  • 1.5 h

  • 6 h

MCQ
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उत्तर

6 h

Explanation:

`k = 2.303/t log((A_0)/(A_t))`

Where,
A0 is the initial concentration,

At is the concentration after time t,

t is the time taken.

`k = 2.303/12 log((0.8)/(0.2))`

`k = 2.303/12 log(4)`

`k = 2.303/12 2log(2)`

`k = 2.303/12 xx 0.6020`

`k = (2.303 xx 0.6020)/12`

`k = 1.384306/12`

k ≈ 0.11536 hr−1

`t_(1//2) = 0.693/k`

`t_(1//2) = 0.693/0.11536`

`t_(1//2) ≈ 6.01` h

The half-life of the first-order reaction is approximately 6 hours.

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अध्याय 6: Chemical Kinetics - Exercises [पृष्ठ १३५]

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बालभारती Chemistry [English] Standard 12 Maharashtra State Board
अध्याय 6 Chemical Kinetics
Exercises | Q 1. vi. | पृष्ठ १३५

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