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प्रश्न
A pendulum consisting of a massless string of length 20 cm and a tiny bob of mass 100 g is set up as a conical pendulum. Its bob now performs 75 rpm. Calculate kinetic energy and increase in the gravitational potential energy of the bob. (Use π2 = 10)
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उत्तर

Data: L = 0.2 m, m = 0.1 kg, n = `75/60 = 5/4` rps,
g = 10 m/s2, π2 = 10,
T = `1/n = 4/5` s = 0.8 s
T = `2pi sqrt((L cos theta)/g)`
∴ T2 = `4pi^2 (L cos theta)/g`
∴ h = L cos θ = `(gT^2)/(4 pi^2)`
= `((10)(0.8)^2)/(4(10))`
= 0.16 m ...(1)
∴ cos θ = `0.16/0.2` = 0.8
∴ θ = cos−1 0.8 = 36.87° = 36°5'
v2 = rg tan θ = (L sin θ)(g) tan 36.87°
= (0.12)(10)(0.7500)
= 0.9
The KE of the bob `= 1/2 mv^2`
= `1/2(0.1)(0.9)`
= 0.045 J
The increase in gravitational PE,
ΔPE = mg (L − h)
= (0.1)(10)(0.2 − 0.16)
= 0.04 J
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