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A Particle of Mass 1 G and Charge 2.5 × 10−4 C is Released from Rest in an Electric Field of 1.2 × 10 4 N C−1. How Long Will It Take for the Particle to Travel a Distance of 40 Cm?

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प्रश्न

A particle of mass 1 g and charge 2.5 × 10−4 C is released from rest in an electric field of 1.2 × 10 4 N C−1.   How long will it take for the particle to travel a distance of 40 cm?

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उत्तर

Given:
Charge of the particle, q = 2.5 × 10−4 C
Initial velocity, u = 0 
Electric field intensity, E = 1.2 × 104 N/C
Mass of the particle, m = 1 g = 10−3 kg
Distance travelled, s = 40 cm = 4 × 10−1 m

Acceleration of the particle, 

\[a = \frac{F_e}{m} = \frac{3}{{10}^{- 3}} = 3 \times  {10}^3  \text{ m/ s}^2\]

Let t be the time taken by the particle to cover the distance s = 40 cm. Then,

\[s = \frac{1}{2}a t^2 \] 

\[ \Rightarrow   t = \sqrt{\frac{2s}{a}} = 1 . 63 \times  {10}^{- 2}   s\] 

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अध्याय 29: Electric Field and Potential - Exercises [पृष्ठ १२२]

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एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
अध्याय 29 Electric Field and Potential
Exercises | Q 48.2 | पृष्ठ १२२

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