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प्रश्न
A nucleus of an element X which has the symbol `""_84^202` X emits an alpha particle and then a beta particle. The final nucleus is `""_"b"^"a"` Y Find a and b.
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उत्तर
Initia I ly element is rep resented by 84X202
a particle is rep resented by 2He4 this means it contains 2 protons and 2 neutrons so mass of a particle is 4 unit. Thus after emitting a particle mass number of element would decrease by 4 unit and atomic number of element would decrease by 2.
So after emitting a particle 84X202 would become 84-2X202-4= 82X198.
13 particle is represented by -1e° after emitting a β particle atomic number of element would increase by 1 unit and mass number of element would remain unchanged.
So after emitting a ~ particle 82X198 would become 82X198 = 83X198.
The daughter nucleus is rep resented by bYa
bYa = 83X198.
a= 198
b= 83.
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