Advertisements
Advertisements
рдкреНрд░рд╢реНрди
A hand fan is made by stitching lo equal size triangular strips of two different types of paper as shown in Fig. 12.28. The dimensions of equal strips are 25 cm, 25 cm and 14 cm. Find the area of each type of paper needed to make the hand fan.

Advertisements
рдЙрддреНрддрд░
Given that the sides of ΔAOB are
AO = 24 cm
OB = 25 cm
BA = 14 cm
Area of each equal strips = Area of Δle AOB
Now, for area of ΔAOB
Perimeter of ΔAOB
Let 2s = AO + OB + BA
`⇒s=1/2(AO+OB+BA)`
`=1/2(25-25-14)=32 cm`
∴ЁЭР╡ЁЭСж ЁЭСвЁЭСаЁЭСЦЁЭСЫЁЭСФ ЁЭР╗ЁЭСТЁЭСЯЁЭСЬЁЭСЫ′ЁЭСаЁЭСУЁЭСЬЁЭСЯЁЭСЪЁЭСвЁЭСЩЁЭСОЁЭСТ
ЁЭР┤ЁЭСЯЁЭСТЁЭСО ЁЭСЬЁЭСУ (ΔЁЭР┤ЁЭСВЁЭР╡)=`sqrt(s(s-ao(s-ob)s-ba))`
`=sqrt(32(32-25)(32-25)(32-14))`
`=sqrt(32(7)(4)(18))`
`=168 cm^2`
∴ Area of each type of paper needed to make the hand fan = 5 ×(ЁЭСОЁЭСЯЁЭСТЁЭСО ЁЭСЬЁЭСУ ΔЁЭР┤ЁЭСВЁЭР╡)
= 5 × 168
= `840 cm^2`
APPEARS IN
рд╕рдВрдмрдВрдзрд┐рдд рдкреНрд░рд╢реНрди
The triangular side walls of a flyover have been used for advertisements. The sides of the walls are 122m, 22m, and 120m (see the given figure). The advertisements yield an earning of тВ╣ 5000 per m2 per year. A company hired one of its walls for 3 months. How much rent did it pay?

The perimeter of an isosceles triangle is 42 cm and its baše is (32) times each of the equal sides. Find the length of each side of the triangle, area of the triangle and the height of the triangle.
Find the area of an isosceles triangle having the base x cm and one side y cm.
Sides of a triangle are cm 45 cm, 39 cm and 42 cm, find its area.
Find the areas of the given plot. (All measures are in metres.)

Find the area of the triangle formed by the points
(1, – 1), (– 4, 6) and (– 3, – 5)
Determine whether the sets of points are collinear?
(a, b + c), (b, c + a) and (c, a + b)
The semi-perimeter of a triangle having sides 15 cm, 20 cm and 25 cm is
The area of the isosceles triangle is `5/4 sqrt(11)` cm2, if the perimeter is 11 cm and the base is 5 cm.
In the following figure, тИЖABC has sides AB = 7.5 cm, AC = 6.5 cm and BC = 7 cm. On base BC a parallelogram DBCE of same area as that of тИЖABC is constructed. Find the height DF of the parallelogram.

