Advertisements
Advertisements
प्रश्न
Find the perimeter and area of the quadrilateral ABCD in which AB = 17 cm, AD =9 cm, CD = l2cm, ∠ACB = 90° and AC=l5cm.
Advertisements
उत्तर
The sides of a quadrilateral ABCD in which AB = 17 cm, AD = 9 cm, CD = 12 cm, ∠ACB = 90° and AC = 15 cm
Here, By using Pythagoras theorem
`BC=sqrt(17^2-15^2) = sqrt(289-225)=sqrt64=8cm`
Now, area of ΔABC=`1/2xx8xx15=60cm^2`
For area of Δle ACD,
Let a = 15 cm, b = 12 cm and c = 9 cm
Therefore, S =`(15+12+9)/2=36/2=18cm`
Area of ACD =`sqrt(s(s-a)(s-b)(s-c))`
`=sqrt(18(18-15)(18-12)(18-9))`
`=sqrt(18xx18xx3xx3)`
`=sqrt((18xx3)^2)`
`=54cm^2`
∴ Thus, the area of quadrilateral ABCD = `60 + 54 = 114 cm^2`
APPEARS IN
संबंधित प्रश्न
A field is in the shape of a trapezium whose parallel sides are 25 m and 10 m. The non-parallel sides are 14 m and 13 m. Find the area of the field.
A park, in the shape of a quadrilateral ABCD, has ∠C = 900, AB = 9 m, BC = 12 m, CD = 5 m and AD = 8 m How much area does it occupy?
Mark the correct alternative in each of the following:
The sides of a triangle are 16 cm, 30 cm, 34 cm. Its area is
The sides of a triangle are 7 cm, 9 cm and 14 cm. Its area is
The sides of a triangle are 50 cm, 78 cm and 112 cm. The smallest altitude is
If the area of an isosceles right triangle is 8 cm2, what is the perimeter of the triangle?
A land is in the shape of rhombus. The perimeter of the land is 160 m and one of the diagonal is 48 m. Find the area of the land.
The adjacent sides of a parallelogram measures 34 m, 20 m and the measure of the diagonal is 42 m. Find the area of parallelogram
The sides of a triangle are 35 cm, 54 cm and 61 cm, respectively. The length of its longest altitude ______.
The area of a regular hexagon of side ‘a’ is the sum of the areas of the five equilateral triangles with side a.
