Advertisements
Advertisements
प्रश्न
Find the area of a quadrilateral ABCD in which AB = 3 cm, BC = 4 cm, CD = 4 cm, DA = 5 cm and AC = 5 cm.
Advertisements
उत्तर
For ΔABC,
AC2 = AB2 + BC2
(5)2 = (3)2 + (4)2
Therefore, ΔABC is a right-angled triangle, right-angled at point B.
Area of ΔABC`= 1/2xxABxxBC=1/2xx3xx4=6 cm^2`
For ΔADC,
Perimeter = 2s = AC + CD + DA = (5 + 4 + 5) cm = 14 cm
s = 14/2 = 7 cm
By Heron’s formula,
`"Area of triangle "=sqrt(s(s-a)(s-b)(s-c))`
`"Area of "triangle ADC=[sqrt(7(7-5)(7-5)(7-4))]cm^2`
`=(sqrt(7xx2xx2xx3))cm^2`
`=2sqrt21 cm^2`
= (2 x 4.583) cm2
= 9.166 cm2
Area of ABCD = Area of ΔABC + Area of ΔACD
= (6 + 9.166) cm2
= 15.166 cm2
= 15.2 cm2 (approximately)
संबंधित प्रश्न
Two parallel side of a trapezium are 60 cm and 77 cm and other sides are 25 cm and 26 cm. Find the area of the trapezium.
Find the area of a quadrilateral ABCD in which AD = 24 cm, ∠BAD = 90° and BCD forms an equilateral triangle whose each side is equal to 26 cm. (Take √3 = 1.73)
Find the area of an equilateral triangle having each side 4 cm.
The perimeter of a triangullar field is 144 m and the ratio of the sides is 3 : 4 : 5. Find the area of the field.
Let Δ be the area of a triangle. Find the area of a triangle whose each side is twice the side of the given triangle.
The sides of a triangle are 50 cm, 78 cm and 112 cm. The smallest altitude is
The sides of a triangle are 11 m, 60 m and 61 m. The altitude to the smallest side is
The lengths of the sides of Δ ABC are consecutive integers. It Δ ABC has the same perimeter as an equilateral triangle with a side of length 9 cm, what is the length of the shortest side of ΔABC?
The length of each side of an equilateral triangle having an area of `9sqrt(3)`cm2 is ______.
The area of the equilateral triangle is `20sqrt(3)` cm2 whose each side is 8 cm.
